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9.5.  MASS TRANSFER WIT73 CONVECTION                                401

           Carrying out the integrations yields


                                                                            (9.598)


           where the average mass transfer coefficient, (k,), is defined by
                                             lL
                                       (kc) =  / kc dz                     (9.599)
                                                0
           The rate of moles of species A transferred to the liquid is
                  nA =    [(cAb>~, - CA,] = e {(c>  - CA,)  - [c:  - (CAb)~])   (9.5100)

           Elimination of   between Eqs.  (9.598) and (9.5100) leads to
                                                      IC;
                                                  )
                                          , qc?-;:$L]
                            nA = (wL)(kc)  (c>  - cA~ -  - (cAb ) L 1     (9.5101)
                                                     +

                                                  (ACA)LM
              When 7 > 0.1, all the terms in Eq. (9.5-92), excluding the first, become almost
           zero, i.e.,
                                                                          (9.5-102)

           The use of  Eq. (9.5102) in Q. (9.598) gives
                                         e
                                  (kc) = - (5.12137 + 0.241)              (9 5-1 03)
                                        WL
           Since we restrict our analysis to long contact times, i.e., 7 is large, then Eq.  (9.5
           103) simplifies to               e

                                     (kc) =     (5.12137)                 (9.5104)
           Substitution of  Eq.  (9.593) into Eq.  (9.5104) and the use of  Q = (v,)Wb gives
                                                 DAB
                                       (k,) = 3.41 -                      (9.5-105)
                                                   6
           Therefore, the average value of  the Sherwood number becomes

                                                                          (9.5106)


           It is also possible to arrive at this result using a different approach (see Problem
           9.17). Equation (9.5106) is usually recommended when

                                                                          (9.5-107)
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