Page 581 - Modelling in Transport Phenomena A Conceptual Approach
P. 581

B.3.  SECOND-ORDER PARTIAL DIFFERENTIAL EQUATIONS                   561

           The choice of  a negative constant is due to the fact that the solution will decay to
           zero as time increases. The choice of a positive constant would give a solution that
           becomes infinite as time increases.
              Note  that  Eq.  (B.3-41) results in two  ordinary differential equations.  The
           equation for F is given by
                                            +
                                        dF
                                        - X2F = 0                          (B.3-42)
                                         dr
           The solution of  Eq. (B.3-42) is

                                         F(T) = e--x2T                     (B.3-43)
           On the other hand, the equation for G is

                                        d2G
                                        -+X2G=0                            (B.3-44)
                                        dt2
           subject to the boundary conditions

                                      at  <=0     G=O                      (B.3-45)
                                      at  <=1     G=O                      (B .3-46)
           Note that  Eq. (B.3-44) is a Sturm-Liouville equation with  a weight function of
           unity.  The solution of Eq. (B.3-44) is

                                  G(<) = Asin(X<) + Bcos(X<)               (B .3-47)
           where A and B are constants. The use of  the boundary condition defined by  Eq.
           (B.3-45)  implies B = 0.  Application of  the boundary condition defined by  Eq.
           (B.3-46) gives
                                          AsinX = 0                        (B.3-48)
           For a nontrivial solution, the eigenvalues are given by
                           sinX=O  *        &=nr       n=1,2,3, ...        (B 3-49)

           The corresponding eigenfunctions are

                                       Gn(<) = sin(nn<)                    (B.3-50)

           Note that each of  the product functions
                                        22
                           e&,  <) = e-n  ?r  sin(n.lr<)   n = 1,2,3, ...   (B.3-51)
           is a solution of Eq.  (B.3-35) and satisfies the initial and boundary conditions, Eqs.
           (B.3-36)-( B.3-38).
              If  61  and 62  are the solutions satisfying the linear and homogeneous partial
           differential equation and the boundary conditions, then the linear combination of
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