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              154    Modern Analytical Chemistry


                                                                        Moles Mg 2+  = 0.060 mol

                                                                                     2–
                                                                      Moles Mg(EDTA) = 0 mol
                                                                     Ca 2+


                                                     log K f,Ca(EDTA) 2– = 10.69


                                                                                        p EDTA

                                                                  Ca(EDTA) 2–


                                                                                         Mg 2+




                                                                                          log K f,Mg(EDTA) 2– = 8.79



                                                                                      Mg(EDTA) 2–
                                                     Figure 6.7
                                                     Ladder diagram for metal–ligand complexes of ethylenediaminetetraacetic acid (EDTA)
                                                                 2+
                                                     with Ca 2+  and Mg .


                                                  We can also construct ladder diagrams using cumulative formation constants
                                              in place of stepwise formation constants. The first three stepwise formation con-
                                                                    2+
                                              stants for the reaction of Zn with NH 3
                                                                                   2+
                                                           2+
                                                        Zn (aq)+NH 3 (aq) t Zn(NH 3 ) (aq)  K 1 = 1.6 ´10 2
                                                                                     2+
                                                            2+
                                                     Zn(NH 3) (aq)+NH 3(aq) t Zn(NH 3) 2 (aq)  K 2 = 1.95 ´10 2
                                                             2+
                                                                                      2+
                                                     Zn(NH 3) 2 (aq)+NH 3(aq) t Zn(NH 3 ) 3 (aq)  K 3 = 2.3 ´10 2
                                                                              2+
                                              show that the formation of Zn(NH 3 ) 3  is more favorable than the formation of
                                                                  2+
                                              Zn(NH 3 ) 2+  or Zn(NH 3 ) 2 . The equilibrium, therefore, is best represented by the
                                              cumulative formation reaction
                                                                                           2+
                                                                 2+
                                                               Zn (aq) + 3NH 3 (aq) t Zn(NH 3 ) 3 (aq)
                                              for which
                                                                       [Zn (NH 3 3   2 + ]
                                                                               )
                                                                                     72 ´
                                                                  b 3 =   2 +     3  = .  10 6
                                                                       [Zn  ][NH 3 ]
                                              Taking the log of each side gives
                                                                               )
                                                                       [Zn (NH 3 3   2 + ]
                                                                                     3
                                                             log b 3 =  log  2 +   – log [NH 3 ]
                                                                          [Zn  ]
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