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Gaussian Optics: The Cardinal Points  33

           Note that a more exact value for the image thickness and the longitudinal
        magnification can be obtained by calculating s′ for two object distances, 1 in
        apart. If we use object distances of  20 in and  21 in, we get an image distance
        difference (image thickness) of 0.038462 in. Using  19 in and  20 in, we get
        0.041667 in. Using  19.5 in and  20.5 ft, the result is an image thickness of
        0.040016 in.

        4 The first principal point of a 2 in focal length lens is 1 in from the object.
        Where is the image, and what is the magnification?
        ANSWER:  Using Eq. 2.5, we find the image at
                                  s′   s   f/(s   f )
                                  s′   1   2/( 1   2)   2/1   2 in
        The image is 2 in to the left of the lens, and the magnification m   s′/s
         2/( 1)   2 .
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