Page 43 - Modern physical chemistry
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32                       Structure in Molecules and Atoms


















                                                  FIGURE  2.5  Apparent cross sections presented
                                                  by the target atoms in thickness !xc of a material
                                  -Mi-            to a given beam.



             number of atoms in this volume is n/).x. The corresponding shading area is an/).x. The
             fraction of incident particles that strike this obstruction, per unit area, must be an/).x.
             But intensity I is proportional to the number of projectile particles reaching this unit area
             in unit time. So we have
                                                M
                                              -- = an/).x.                           [2.36]
                                                I
                We suppose that the cross sections in one atomic layer do not cast effective shadows
             on those in successive atomic layers. We also suppose that the thickness of each of these
             layers is relatively small so that the increments can be replaced by differentials. In this
             continuum approximation, equation (2.36) becomes

                                              _ dI =andx.                            [2.37]
                                                I
             Integrating (2.37) over the thickness x yields

                                                 I
                                              In-=-anx.                              [2.38]
                                                In
             Here 10 is the intensity of the beam at x = 0 while I is its intensity after traveling distance
             x through the absorbing medium.
                A convenient unit for nuclear reactions is the barn, defined as 10- 28  m 2  (10- 24  cm 2 ).


             Example 2.3
                A beam ofthennal neutrons is reduced to 0.0100 percent of its initial intensity by 0.083
             cm of cadmium. Calculate the cross section presented by a cadmium atom to the beam.
                Solve equation (2.38) for the cross section:





                                                    nx
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