Page 117 - Numerical Analysis Using MATLAB and Excel

Chapter 3 Sinusoids and Phasors

ans =

1.5301 + 0.1008i
ans =

3.6883 - 0.7337i
4.
a.
– 1 ( 5 9 ) j0.5071
⁄
2
2
j tan
5 ⋅
106 e ⋅
j5
9 +
9 +
e
------------------ = -------------------------------------------------------- = ----------------------------------- = 2.3022e j – 3.0981
–
– 4 j2 2 2 j tan – 1 – ( 2 – 4 ) j3.6052
⁄
4 + 2 ⋅ e 20 e ⋅
∠
= 2.3022e – j177.5081° = 2.3022 – 177.5081°
⁄
2 2 j tan – 1 ( 3 – 8 ) – j0.3588
73 e
3 ⋅
e
8 +
– 8 + j3 ------------------------------------------------------ = ---------- ------------------ = 1.9105e j0.7483
⋅
------------------ =
b. – 2 + j4 2 + 4 ⋅ e j tan – 1 ( 4 – 2 ) 20 e – j1.1071
⁄
2
2
∠
= 1.9105e j42.8744° = 1.9105 42.8744°
Check with MATLAB:
x=(9+5j)/(−4−2j); abs(x), angle(x)*180/pi,...
y=(−8+3j)/(−2+4j); abs(y), angle(y)*180/pi
ans =
2.3022
ans =
-177.5104
ans =
1.9105
ans =

42.8789
5.
a.
∠
430°
)
⁄
---------------------- = ( 4 5 ∠ 180° = – 0.8
∠
5 – 150°
j60°
e
)
)
(–
( –
b. ------------------- = 0.5e j90° = – 0.5 cos 90° + jsin 90° = 0.5 0 + j = – j0.5
– 2e – j30°
3−30 Numerical Analysis Using MATLAB® and Excel®, Third Edition
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