Page 103 - Numerical Methods for Chemical Engineering
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92      2 Nonlinear algebraic systems



                   The first moment is unchanged by the reaction, as is expected since the total number of
                   monomer units is conserved. The equation for the second moment requires that we know
                   the value of the third moment. To obtain a closed set of equations, it is common to postulate
                   a mathematical form of the chain length distribution (see Chapter 7) to relate the unknown
                   λ 3 to the known λ 0 , λ 1 , λ 2 . This approach yields the closure approximation

                                                             2
                                                  λ 2 2λ 2 λ 0 − λ 1
                                              λ 3 ≈                                  (2.127)
                                                       λ 1 λ 0


                   Steady-state model of a stirred-tank polycondensation reactor
                   We now use these results to model the steady-state behavior of a polycondensation CSTR.
                   The mole balance on m-mer is
                                     d            (in)  (in)
                                       {M[P m ]}= F  [P m ]  − F[P m ] + Mr P m      (2.128)
                                     dt
                   Here, we represent concentrations on a per-mass basis, due to volume changes during
                   reaction. M is the total mass of the reaction medium in the reactor. F (in)  and F are the inlet
                   and outlet mass flow rates.
                     The first term on the right-hand side of (2.128) is the flux of m-mer into the reactor from
                   the inlet stream, the second term is the flux of m-mer out of the reactor, and the last term
                   is the rate of change of m-mer concentration due to chemical reaction. Multiplying this
                              k
                   equation by m and summing over all m yields
                                    (
                                            ∞
                           ∞
                                                            ∞
                                                                          ∞
                     d    	    k         (in)  	  k  (in)  	    k        	    k
                        M     m [P m ] = F     m [P m ]  − F  m [P m ] + M  m r P m  (2.129)
                    dt
                          m=1               m=1            m=1           m=1
                   This is simply the balance for the kth moment, and at steady state yields
                                      d              (in) (in)
                                        {Mλ k } = 0 = F  λ k  − Fλ k + Mr λ k        (2.130)
                                      dt
                   With λ 1 held constant (as it is unchanged by the reaction), we have
                       d              (in) (in)          2        −1
                         {Mλ 0 } = 0 = F  λ 0  − Fλ 0 − Mk fc λ + Mk fc K eq  [W](λ 1 − λ 0 )
                                                         0
                       dt
                      d               (in) (in)          2        −1      1
                        {Mλ 2 } = 0 = F  λ 2  − Fλ 2 + 2Mk fc λ + Mk fc K eq  [W] λ 1 − λ 3  (2.131)
                                                                         3
                                                         1
                      dt
                   and for λ 3 use the auxiliary moment closure equation
                                                             2
                                                  λ 2 2λ 2 λ 0 − λ 1
                                              λ 3 ≈                                  (2.132)
                                                       λ 1 λ 0
                   We contact the reaction medium with a purge gas stream to remove the water, such that the
                   total mass balance on the reaction medium is

                                           F = F (in)  − (k m a)M M W [W]            (2.133)
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