Page 164 - Offshore Electrical Engineering Manual
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Lighting Calculations  151




                  UTILISATION FACTORS FOR INTERIORS AND AVERAGE ILLUMINANCE
                  The utilisation factor UF(S) for a surface S is the ratio of the total flux received by S
                  to the total lamp flux of the installation. Utilisation factors are used to calculate the
                  number of luminaires needed to provide a given illuminance on a surface. UFs vary
                  according to the light distribution of the luminaire, the geometry of the room, the
                  layout of the luminaires and the reflectance of the reflecting surfaces.
                     The average horizontal illuminance E (S) produced by a lighting installation, or
                                                   h
                  the number of luminaires required to achieve a specific average illuminance, can
                  be calculated by means of utilisation factors using the ‘lumen method’ formula as
                  follows:-
                                            F × n × N × MF × UF (S)
                                      E (S) =
                                                   A h (S)
                  where F is the initial bare lamp flux, n is the number of lamps per luminaire, N is the
                  number of luminaires, MF is the maintenance factor associated with the deterioration
                  due to dirt, dust and lamp ageing, A (S) is the area of the horizontal reference surface
                                              h
                  S and UF(S) is the utilisation factor for the reference surface S.
                    Although utilisation factors may be calculated by the lighting designer (see
                  Bibliography), most manufacturers publish utilisation factors for standard conditions
                  of use and for three main room surfaces. The first of these surfaces, the C surface
                  is an imaginary horizontal plane at the level of the luminaires, having a reflectance
                  equal to that of the ceiling cavity. The second surface, the F surface, is a horizontal
                  plane at normal working height which is usually assumed to be 0.85 m above the
                  floor. The third surface, the W surface, consists of all the walls between the C and F
                  planes. A typical table of utilisation factors is shown in Fig. 2.14.5.
                     The room index is a measure of the angular size of a room, and is the ratio of the
                  sum of the areas of the F and C surfaces to the area of the W surface, each rectangular
                  area of room being treated separately. For rectangular rooms, the room index is given
                  by:-
                                                    LW
                                             RI =
                                                 (L + W) H
                  where L is the room length, W is the room width, and H is the height of luminaire
                  plane above the horizontal reference plane.  The  effective reflectances (ratio of
                  reflected flux to incident flux) are needed for the wall surface, ceiling cavity and the
                  floor cavity.
                     The wall surface will consist of a series of areas A  to A  of different reflectances
                                                            1
                                                                 n
                  R  to R  respectively. The effective reflectance of a composite surface is the area-
                        n
                   1
                  weighted average R , given by:
                                  a
                                                   n  RkAk
                                                 ∑
                                                   k= 1
                                                    n
                                            R a = ∑
                                                    k= 1  Ak
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