Page 132 - Physical Principles of Sedimentary Basin Analysis
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114                             Heat flow
                     Table 6.2. The abundance of the elements U, Th and K in some rocks. The first
                     data set is taken from Van Schmus (1995), the second is from Perry et al. (2006),
                     the third is from Rudnick and Fountain (1995) and the fourth is from Turcotte
                     and Schubert (1982).

                                        U      Th    K      S total
                     Name               (ppm)  (ppm)  (%)   (μWm −3 )  C Th /C U  C K /C U
                     Granite (1)        3.4    50    4.45   4.8       14.7     1.3
                     Granite (2)        3.0    24    3.67   2.8        8.0     1.2
                     Granite (low Ca)   4.7    20    4.2    3.0        4.3     0.9
                     Marine mud         2.8    12.2  2.96   1.9        4.4     1.1
                     Shale              3.1     9.5  2.2    1.7        3.0     0.7
                     Sandstone          1.7     5.5  1.07   0.9        3.2     0.6
                     Peridotite         0.005   0.01  0.001  0.002     2.0     0.2
                     Ultramafic intrusives  0.24  0.85  0.69  0.19      3.5     2.9
                     Gneiss, metasediments  1.86  6.89  1.93  1.15     3.7     1.0
                     Gabbro             0.23    0.9  0.27   0.15       3.9     1.2
                     Av. continental crust  1.6  5.8  2.0   1.0        3.6     1.3
                     Av. oceanic crust  0.9     2.7  0.4    0.47       3.0     0.4
                     Undepleted mantle  0.02    0.1  0.02   0.01       5.0     1.0



                 per unit time for an unstable nucleus. Equation (6.42) is straightforward to integrate, and
                 gives the number of atoms as a function of time

                                                N = N 0 e −λt                       (6.43)
                 where N 0 is the number of atoms at time t = 0. It is often interesting to know how long it
                 takes for the number of atoms to be reduced by half. We then have to solve the equation
                                                     1    −ln2
                                             e −λt 1/2  =  = e                      (6.44)
                                                     2
                 which has the solution t 1/2 for the half-life
                                                  ln2   0.693
                                            t 1/2 =   =      .                      (6.45)
                                                   λ      λ
                 The heat production for each radioactive isotope decays with its own time constant and the
                 total heat production per unit mass of rock is
                                                           −λ i t
                                            H(t) =   C i H i e                      (6.46)
                                                   i
                 where the index i is according to Table 6.1. Figure 6.3 shows the heat production for the
                 average continental crust (see Table 6.2) for the past 4 Ga. The total heat production was
                 14% higher in the crust 500 Ma years ago, and 2 times higher 2.5 Ga ago. The decay in
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