Page 173 - Physical Principles of Sedimentary Basin Analysis
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6.14 Instantaneous heating or cooling of semi-infinite half-space  155

            instantaneous heating or cooling of the semi-infinite half-space is a useful starting point
            for other similar problems, like cooling sills or dikes, and the thermal structure of the
            lithosphere.
              The semi-infinite half-space has a surface at z = 0 and it covers the entire z-axis below
            the surface. The temperature of the half-space is initially at T 0 (for t < 0), but at t = 0the
            surface temperature is suddenly changed to T s . The general temperature equation (6.15)
            simplifies in this case to
                                                 2
                                         ∂T    ∂ T
                                            − κ     = 0                       (6.201)
                                         ∂t     ∂z 2
            where κ = λ/(c b   b ) is the thermal diffusivity. The boundary conditions are the surface
            temperature T (z=0, t) = T s and the temperature T = T 0 at infinite depth (for z →∞).
            Note 6.7 shows that the solution of the temperature equation becomes

                                                           z
                               T (z, t) = T 0 + (T s − T 0 ) erfc  √  ,       (6.202)
                                                         2 κt
            where erfc(η) is a special function called the complementary error function. It is defined as

                                       erfc(η) = 1 − erf(η)                   (6.203)
            in terms of the error-function erf, which is given by the integral
                                             √    η
                                              π      −x  2
                                     erf(η) =       e  dx.                    (6.204)
                                              2   0
            The error function and the complementary error function are shown in Figure 6.24,see
            also Exercise 6.22. The temperature solution could also have been written
                                                           z

                                T (z, t) = T s + (T 0 − T s ) erf  √          (6.205)
                                                         2 κt

                               1.0

                               0.8
                                           erf(x)

                               0.6

                               0.4

                                           erfc(x)
                               0.2


                               0.0
                                 0.0  0.5  1.0  1.5  2.0  2.5  3.0
                                                x
            Figure 6.24. The erf and erfc functions.
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