Page 59 - Physical Principles of Sedimentary Basin Analysis
P. 59

3.4 Strain                            41

                                       du 1



                                      φ 2
                                 dx 2
                                              φ


                                                   φ 1      du 2
                                              dx 1

            Figure 3.3. The deformation of a right angle.

            and an antisymmetric part
                                            1     ∂u i  ∂u j
                                      R ij =       −                           (3.10)
                                            2  ∂x j  ∂x i
            (ε ij is symmetric because ε ij = ε ji , and R ij is antisymmetric because R ij =−R ji .) The
            reason for expressing ∂u i /∂x j as these two parts is that the symmetric part ε ij expresses
            volume and shape changes, while the antisymmetric part R ij expresses rotations. We
            will later see that we have to distinguish rotations from volume and shape changes when
            deformation (strain) is related to forces (stress).
              We have already observed that a diagonal element of the symmetric part ε ij , for instance
            ε 11 , represents relative length change in the x-direction. (If two points along the x-axis, x 1
            and x 1 + dx 1 , become displaced by u 1 (x 1 ) and u 1 (x 1 + dx 1 ) respectively, then the relative
            length change between the points is du 1 /dx 1 ≈ ∂u 1 /∂x 1 = ε 11 .)
              The off-diagonal elements of ε ij are the amount a right-angle becomes deformed. See
            Figure 3.3, where we have that φ 1 ≈ du 2 /dx 1 and φ 2 ≈ du 1 /dx 2 , because we can make
            the approximation tan φ ≈ φ for small angles (resulting from small deformations). The
            right-angle then becomes deformed by an amount

                                            du 1  du 2
                                   φ 1 + φ 2 =  +     = 2 ε 12 .               (3.11)
                                            dx 2  dx 1
            The off-diagonal term ε 12 is thus one-half the amount a right-angle becomes deformed.
            The interpretation of the two other off-diagonal elements ε 13 and ε 23 is similar.
              It is the sum of the diagonal elements of ε ij that expresses local volume changes. This
            is seen by considering a rectangular box with sides dx i (i = 1, 2, 3) before it is deformed.
            The sides of the box are dx i + du i after the deformation, where du i is the difference in
            displacement of the two diagonal opposite corners x and dx, see Figure 3.4. The difference
            in volume of the box caused by the deformation is then

                            dV = du 1 dx 2 dx 3 + dx 1 du 2 dx 3 + dx 1 dx 2 du 3

                                   du 1  du 2  du 3
                                =      +     +      dx 1 dx 2 dx 3             (3.12)
                                   dx 1  dx 2  dx 3
   54   55   56   57   58   59   60   61   62   63   64