Page 222 - Pipeline Rules of Thumb Handbook
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Corrosion/Coatings  209

           How to calculate the voltage drop in ground bed cable quickly


             Use the following formula for calculating the voltage drop
           in a copper ground bed cable:

               R 1000
                     T [
                                  1
           V T =    ID GR +  D A ( [  N - )( )
                                    I T
               1000
                                   1
               - I A (1 +++234 ....  N - )]]
           where   V T = total voltage drop in volts
                  R 1000 = cable resistance per 1,000ft
                    I T = total current in amperes
                    I A = I T /N current per anode
                  D GB = distance from rectifier to first anode in ft
                   D A = distance between anodes in ft
                    N = number of anodes in ground bed
                                                                     .2487
                                                                                       [
                                                                                       ()(225
             Example. What is the voltage drop in a copper wire  V T =  , 1 000  ( [ 225 )(100 )+ 20 15  )
           ground bed cable in a cathodic protection system having a         )]]
                                                                       14
           rectifier output of 225 amperes? The distance from rectifier  -()(120
           to ground bed is 100ft and 16 anodes are spaced on 20ft
           centers. The cable used is No. 4 copper having a resistance  V T =  .2487  ( ,22 500 + 20 695 ])
                                                                                    [ ,1
           of 0.2487 ohm per 1,000ft.                                 , 1 000
           Then  R 1000 = 0.2487 ohm                             V T =  Ê .2487 ˆ ( ,56 400 )
                   I T = 225 amperes                                 Ë ,1 000 ¯
                   I A = 225/16 = 14 amperes
                 D GB = 100ft                                    V T = (.2487 )( .56 4 )
                  D A = 20ft
                   N = 16                                        V T = 14 .00 volts drop










           What is the most economical size for a rectifier cable?


             Choosing the economical size for a rectifier cable in-  cables, and assumes the use of a good grade of direct burial
           volves balancing the first cost of the cable against the   cable.
           power losses. A rule which does not include all of the factors,
           but which usually gives a very close approximation, is as  Example. Suppose
           follows:
                                                                 I = 60 amps
                                                                 P = 4 cents
           a = 2 280 I P
               ,
                                                                 a = (2 280 )( )(60  ) 4
                                                                     ,
           where a is the area of the cable in circular mils (refer to a   a = 273 600 circular mils
                                                                       ,
           wire table for size), I is the current to be carried, in am-
           peres, and P is the cost of power in cents per kilowatt-hour.  Cable is sized 250,000 and 300,000 circular mils. Use the
           This formula is based on the present prices of copper   latter.
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