Page 226 - Pipeline Rules of Thumb Handbook
P. 226

Corrosion/Coatings  213

           How can the life of magnesium anodes be predicted?


             Multiply the anode weight in lb by 57, and divide by the  The projected life is 11.7 years.
           current output in milliamperes.                         The rule is based on 50% current efficiency, and on sta-
                                                                 bilized conditions. If more anodes are to be added, or if
             Example. A 17-lb anode has a current output of 83 mil-  time has not been allowed for polarization (one to four
           liamperes. What is its projected life?                weeks), then the current output will probably fall off, and
                                                                 the actual life will be 10 to 40% longer than indicated by
           17 ¥ 57/83 = 11.7                                     the rule.





           How to find the voltage rating of a rectifier if it is to deliver a given amount of current through a given
           ground bed (graphite or carbon)


             Multiply the desired current, in amperes, by the total resis-  ( 20 ¥  0 9)+=  20 volts
                                                                      .
                                                                          2
           tance of the ground bed, in ohm (either calculated or mea-
           sured); add two volts, to overcome the galvanic difference  Specify the next larger size, which will probably be (depend-
           between graphite and protected steel.                 ing upon the manufacturer) 24 volts.

                                                                   Note. Where the resistance is measured rather than cal-
                                                                 culated, and is the total loop resistance between pipe and
             Example. A current of 20 amperes is desired from a  ground bed, this method is quite precise; for calculated
           ground bed whose resistance is 0.9 ohm.               values, caution should be observed.





           Determining current requirements for coated lines


             Survey along the line after a polarization run of three or
           four hours, and locate the two points whose pipe-to-soil
           potentials are 1.0 volt and 0.8 volt (see Figure 1). The section
           of line lying between these two points will then be at an
           average potential of about 0.9 volt, which is approximately the
           average of a line protected with distributed magnesium
           anodes. If, then, the line current is measured at each of these
           two points, the difference between these two line currents
           will be the total amount of current picked up on the line in
           the section. This quantity, divided by the length of the section,
           will then give the current requirements of the line, in amperes  line if the section chosen is truly representative; judgment
           per mile. Naturally this figure can only be used for an entire  must be used at this point.




           Determining current requirements for coated lines when pipe-to-soil potential values are estimated


             If it is not possible or convenient to find the points which  line current can then be adjusted to find the desired quantity;
           have the exact values of 1.0 and 0.8, then readings can be  this is illustrated in Figure 1; readings were taken at points
           taken which approximate these values, and both potential and  “A” and “B,” and, by assuming a static potential of 0.6 volt and
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