Page 242 - Plastics Engineering
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Mechanical Behaviour of  Composites                            225

                In this case [B] # 0 and so [a] and [d] cannot be obtained by inverting the [A]
                and [D] matrices respectively. They must be obtained from
                                        [;  :]        ;]-l
                                                  [;
                                               =
                The  in-plane  strains and  the  moments and  curvatures  are  all  linked  in  this
                non-symmetrical lamina and are obtained from

                                    all   a12   a16   bll  b12   b16
                                    a21   a22   a26   b21   b22   b26
                                    a61   a62   a66   b61   b62  b66
                                    811   812   816   dll  d12  d16
                                    821   822   86  d21   d22   d26
                                    861   862   866   d61   d62  d66
                where
                                      N = 0. h(Nx = 50 N/mm)
                which gives the strains and curvatures as
                  ex = 3.326 x         cy = -2.868  x         yxy  = -3.405  x  IOv5

                  Kx  = 0.012 IlUl-',   Ky  = -0.01  mm-',   K~~  = 0.019 mm-'
                The important point to note from this Example is that in  a non-symmetrical
                laminate the behaviour is very complex. It can be seen that the effect of a simple
                uniaxial stress, ax, is to produce strains and curvatures in all directions. This
                has relevance in a number of polymer processing situations because unbalanced
                cooling (for example) can result in layers which have different properties, across
                a moulding wall thickness. This is effectively a composite laminate structure
                which is likely to be non-symmetrical and complex behaviour can be expected
                when loading is applied.
                  The reader may  wish to check the matrices in this Example:
                              14.37:  io4  1.41  io4
                         A =  1.41 x  lo4  1.27 x  104
                                              0      1.40 x  104
                                6.65   10-~  -5.73   10-~  -6.81   0-7
                                                                   0-5]
                               -6.81  x      -2.05  x       1.02 x  0-4
                         B= [  -1.46  x  io3   604.5  -1.67  x  io3  1
                                                      -792
                                             258.2
                                  604.5
                               -16.7  x  lo3  -792      604.4
                                2.30   10-~  -2.09   10-~   3.77   10-~
                               -2.24  x       1.49 x        5.34 x
                                9.55  10-~  2.01     10-~  -2.03  x  10-~
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