Page 231 - Principles and Applications of NanoMEMS Physics
P. 231

A. QUANTUM MECHANICS PRIMER                                   221


               Other commutation relations are obtained as follows. For bosons, taking
             the hermitian conjugate of (A.31) yields,

               a α a =  a β a .                                                                                   (A.33)
                   β
                          α
             In addition, the facts that  a α  0 =  0  and  a α a + β  0 = δ αβ  0 , mean that we
                          +      +
             can write  a α a β  0 − a β a α  0 = δ αβ  0 , since the second term is zero, so
             that we also have the commutation relation,
                        +
               a α a + β  − a β a α  =  δ αβ .                                                                         (A.34)
               The operator whose  eigenvalue  measures the  number of particles in  a
             given state, say, state α, is the number operator, given by,
                      +
               N =   a α a ,                                                                                       (A.35)
                        α
                 α
             whereas the  total  number of particles, including  all the  distinct  states,  is
             given by,

               N     =  ¦  N .                                                                                 (A.36)
                 Total     α
                        α
             To measure (count) the number of particles in a given state, the operator N is
             applied to that state’s eigenvector. The eigenvector of a state populated by n
             particles is described by the application of the creation operator n times, i.e.,
                 +  n      +  +  +
                              ...a
                            a
               ( ) 0a  =  a         0 ,                                                                  (A.37)

                             n
             so, measuring its occupation is effected by,
                   +  n       +  +   +      +    +  +   +
               N ( ) 0a  =  N a     ...a  0 =  a  a  a ⋅    a  ...a  0 .                       (A.38)
                               a




                                 n                  n
             Now, using the commutation relation  (A.34), we  can  substitute
                +       +
             aa →1   +  a  a  in (A.38), so it becomes,
                   +  n       +  +   +      +      +    +  +   +
                                                      ⋅
                               a
                                                         a
               N  ( ) 0a  =  N  a     ...a  0 =  a  1 ( +  a  a  ) a     ...a  0




                                 n                        n − 1
                                          +
                         =  a  +  a  +  2 ( +  N  )a   +    ... a  +  0 =  ...  .          (A.39)
                                         a

                                          n −  2
                         =  a   +   +    +  (n +  N  )  0
                             a
                               ...a
                              n
                         =  ( ) (na  +  n  +  a  +  ) a  0 =  n  ( ) 0a  +  n
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