Page 111 - Probability Demystified
P. 111

100                                  CHAPTER 6 The Counting Rules

                                 EXAMPLE: In how many different ways can 6 people be arranged in a row
                                 for a photograph?

                                 SOLUTION:

                                 This is a permutation of 6 objects. Hence 6! ¼ 6   5   4   3   2   1 ¼ 720 ways.


                                   In the previous example, all the objects were used; however, in many
                                 situations only some of the objects are used. In this case, the permutation rule
                                 can be used.
                                   The arrangement of n objects in a specific order using r objects at a time is
                                 called a permutation of n objects taking r objects at a time. It is written as n P r
                                 and the formula is
                                             n!
                                      n P ¼
                                        r
                                           ðn   rÞ!


                                 EXAMPLE: In how many different ways can 3 people be arranged in a row
                                 for a photograph if they are selected from a group of 5 people?

                                 SOLUTION:
                                 Since 3 people are being selected from 5 people and arranged in a specific
                                 order, n ¼ 5, r ¼ 3. Hence, there are
                                              5!      5!  5   4   3   2!
                                       P ¼         ¼    ¼            ¼ 5   4   3 ¼ 60 ways
                                      5  3
                                            ð5   3Þ!  2!      2!


                                 EXAMPLE: In how many different ways can a chairperson and secretary be
                                 selected from a committee of 9 people?

                                 SOLUTION:

                                 In this case, n ¼ 9 and r ¼ 2. Hence, there are 9 P 2 ways of selecting two people
                                 to fill the two positions.
                                              9!      9!  9   8   7!
                                        2
                                      9 P ¼        ¼    ¼         ¼ 72 ways
                                            ð9   2Þ!  7!     7!
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