Page 147 - Probability Demystified
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136                   CHAPTER 8 Other Probability Distributions


                                 ANSWERS

                                     1. a ¼ 5, b ¼ 7, n ¼ 5, x ¼ 2, n   x ¼ 5   2 ¼ 3
                                                             2
                                                               7
                                        The probability is  5 C   C 3  ¼  10   35    0:442
                                                            12 C 5     792
                                     2. a ¼ 10, b ¼ 8, n ¼ 6, x ¼ 3, n   x ¼ 3
                                                            C   C     120   56
                                                          10  3  8  3
                                        The probability is          ¼           0:362
                                                             18 C 6   18; 564
                                     3. a ¼ 6, b ¼ 4, n ¼ 3, x ¼ 3, n   x ¼ 3   3 ¼ 0
                                                           C   C  0  20   1
                                                             3
                                                          6
                                                               4
                                        The probability is         ¼       ¼ 0:167
                                                            10 C 3    120
                                     4. a ¼ 5, b ¼ 4, n ¼ 3, x ¼ 3, n   x ¼ 3   3 ¼ 0
                                                               4
                                                             3
                                        The probability is  5 C   C 0  ¼  10   1    0:119
                                                             9 C 3     84
                                     5. a ¼ 3, b ¼ 3, n ¼ 2, x ¼ 2, n   x ¼ 2   2 ¼ 0
                                                           C   C     3   1
                                                          3  2  3  0
                                        The probability is         ¼      ¼ 0:2
                                                             6 C 2    15

                     The Geometric Distribution


                                 Suppose you flip a coin several times. What is the probability that the first
                                 head appears on the third toss? In order to answer this question and other
                                 similar probability questions, the geometric distribution can be used. The
                                 formula for the probability that the first success occurs on the nth trial is
                                            n 1
                                      ð1   pÞ  p
                                 where p is the probability of a success and n is the trial number of the first
                                 success.

                                 EXAMPLE: A coin is tossed. Find the probability that the first head occurs
                                 on the third toss.


                                 SOLUTION:
                                                                         1
                                 The outcome is TTH; hence, n ¼ 3 and p ¼ , so the probability of getting two
                                                                         2
                                                                1
                                                        1
                                                            1
                                                          1
                                 tails and then a head is     ¼ .
                                                        2  2  2  8
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