Page 149 - Probability Demystified
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138                   CHAPTER 8 Other Probability Distributions

                                 SOLUTION:

                                                                                          1
                                 Since there are 13 clubs in a deck of 52 cards, PðclubÞ¼  13  ¼ . The expected
                                                                                      52
                                                                                          4
                                                                                             1
                                 number of trials for selecting two clubs would be   2 1 or 2   ¼ 2   4 ¼ 8
                                                                                             4
                                 trials.                                             4
                                   This type of problem uses what is called the negative binomial distribution,
                                 which is a generalization of the geometric distribution.
                                   Another interesting question one might ask is, ‘‘On average how many
                                 rolls of a die would it take to get all the faces, one through six, on a die?’’ In
                                 this case, the first roll would give one of the necessary numbers, so the
                                 probability of getting a number needed on the first roll would be one. On the
                                                                                              5
                                 second roll, the probability of getting a number needed would be since there
                                                                                              6
                                 are 5 remaining needed numbers. The average number of rolls would be
                                         6
                                 ð  1  Þ or . Since two numbers have been obtained, the probability of getting
                                  5=6    5
                                                          4
                                                                                                       6
                                 the next number would be . The average number of rolls would be ð  1  Þ or .
                                                          6                                      4=6   4
                                 This would continue until all numbers are obtained. So the average number
                                 of rolls it would take to get all the numbers, one through six, would be
                                        6
                                            6
                                     6
                                               6
                                                  6
                                 1 þ þ þ þ þ ¼ 14:7. Hence on average it would take about 14.7 rolls
                                     5  4   3  2  1
                                 to get all the numbers one through six.
                                 EXAMPLE: A children’s cereal manufacturer packages one toy space craft in
                                 each box. If there are 4 different toys, and they are equally distributed, find
                                 the average number of boxes a child would have to purchase to get all four.
                                 SOLUTION:
                                                          2
                                                        3
                                                                  1
                                 The probabilities are 1, , , and . The average number of boxes for each
                                                                  4
                                                          4
                                                        4
                                                                                     4
                                                                                  4
                                                                              4
                                 are  1  ,  1  ,  1  , and  1  so the total is 1 þ þ þ ¼ 8  1  which would
                                     1  ð3=4Þ  ð2=4Þ  ð1=4Þ                   3   2  1    3
                                 mean a child on average would need to purchase 9 boxes of cereal since he
                                 or she could not buy  1  of a box.
                                                     3
                                 PRACTICE
                                     1. A card from an ordinary deck of cards is selected and then replaced.
                                        Another card is selected, etc. Find the probability that the first club
                                        will occur on the third draw.
                                     2. A die is tossed until a one or a two is obtained. Find the expected
                                        number of tosses.
                                     3. On average how many rolls of a die will it take to get 3 fours?
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