Page 80 - Probability Demystified
P. 80

CHAPTER 4 The Multiplication Rules                                          69

                         3. There are 2 black aces and 26 black cards; hence, P(ace|black
                            card) ¼  2  or  1  or
                                   26   13
                                                  P(ace and black card)
                              P(ace black cardÞ¼
                                    j
                                                      P(black card)
                                                     2
                                                    52
                                                ¼
                                                    26
                                                    52
                                                  2    26
                                                ¼
                                                  52   52
                                                   2 1  52 1
                                                ¼
                                                  52 1  26 13
                                                  1
                                                ¼
                                                  13

                         4. P (Sand CrabjRainbow Gardens)
                                                       P(Sand Crab and Rainbow Gardens)
                                                     ¼
                                                               P(Rainbow Gardens)
                                                       0:20
                                                     ¼      ¼ 0:25
                                                       0:80


                         5. There is one way to get 3 twos—(2, 2, 2) and there are 10 ways to get
                            a sum of six—(2, 2, 2), (3, 2, 1), (1, 2, 3), (2, 1, 3), (2, 3, 1), (3, 1, 2),
                            (1, 3, 2), (4, 1, 1), (1, 4, 1,) and (1, 1, 4). Hence,
                                                   P(3 twos and sum of 6)
                              P(3 twosjsum of 6) ¼
                                                         P(sum of 6)
                                                       1
                                                      36
                                                 ¼
                                                      10
                                                      36
                                                    1   10
                                                 ¼
                                                   36   36
                                                    1   36 1
                                                 ¼
                                                   36 1  10
                                                    1
                                                 ¼
                                                   10
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