Page 78 - Probability and Statistical Inference
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1. Notions of Probability  55

                              1.4.16 Consider the digits 0, 1, ..., 9. Use these digits at random to form a
                           four (five) digit number. Then, find the probability  of forming
                                (i)   a four digit random number, not starting with a zero, which
                                      would be an even number while each digit appears exactly once;
                                (ii)  a four digit random number which would be an even number
                                      where the digits can be repeated, and starting with a zero is
                                      allowed;
                                (iii)  a five digit random number, not starting with a zero, which would
                                      be divisible by the number five while each digit appears only
                                      once.
                              1.4.17 In a twin engine plane, we are told that the two engines (#1, #2)
                           function independently. We are also told that the plane flies just fine when at
                           least one of the two engines are working. During a flying mission, individually
                           the engine #1 and #2 respectively may fail with probability .001 and .01.
                           Then, during a flying mission, what is the probability that the plane would
                           crash? The plane would complete its mission?
                              1.4.18 Suppose that A , ..., Ak are disjoint events. Let B be another event.
                                                1
                           Then, show that



                              1.4.19 Suppose that A , A  are events. Then, show that
                                                1  2


                              1.4.20 Suppose that A , A  are disjoint events. Then, show that
                                                1  2
                                (i)   P(A  |   )= P(A )/{1 – P(A )} if P(A ) ≠ 1;
                                         1          1         2       2
                                (ii)  P(A  | A  ∪ A ) = P(A )/{P(A ) + P(A )}.
                                         1   1    2       1     1      2
                              1.5.1 Suppose that a random variable X has the following pmf:
                                  X values:     –2      0      1      3      8
                                  Probabilities:  .2    p      .1     2p     .4

                           where p ∈ (0, .1].
                                (i)   Is it possible to determine p uniquely?
                                (ii)  Find P{|X – .5| > 2} and P{|X – .5| = 2.5}.

                              1.5.2 Suppose that a random variable X has the following pmf:
                                  X values:     –2      0      1          3  8
                                  Probabilities:  .2    p      .1     .3 – p  .4
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