Page 193 - Rotating Machinery Pratical Solutions to Unbalance and Misalignment

Appendices

Step 3. From Table (D-1) a 9/16-in. bit removes .0310631 cubic
inches per 1/8 inch past the tip. Therefore, the number of 1/8-inch
increments is .024/.0310631 = .7726 x .125 or .0966 inches past the
tip.

Since this depth would be difficult to measure, a better solu-
tion may be to use a 1/2-inch bit. The 1/2-inch tip removes
.0084273 cubic inches leaving .035999 - .0084273 or .02757 cubic
inches. The 1/2-inch bit removes .0245437 per 1/8 inch or .125
inch of depth, and thus the required depth is (.02757/.0245437) x
.125 or .14 inches.
Also note that multiple holes can be drilled at different radi-
uses and/or the removed weight can be broken into parts as with
the correction weights.