Page 297 - Satellite Communications, Fourth Edition
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Analog Signals  277

                              used. Denoting the decibel value as gdB, then the voltage ratio is
                              obtained from

                                                                gdB
                                                         g 5 10  / 20                    (9.17)
                                The peak deviation also will depend on the number of channels, and
                              this is taken into account through use of a loading factor, L. The rele-
                              vant CCITT formulas are

                                           For n   240: 20logL   15   10logn             (9.18)
                                           For 12   n   240: 20logL   1   4logn          (9.19)

                                Once L and g are found, the required peak deviation is obtained from
                              the tabulated rms deviation as

                                                              #  #
                                                       F   g    L     F rms              (9.20)
                                The required IF bandwidth can now be found using Carson’s rule,
                              Eq. (9.1), and the processing gain from Eq. (9.16). The following example
                              illustrates the procedure.

                                Example 9.5 The carrier-to-noise ratio at the input to the demodulator of an
                                FDM/FM receiver is 25 dB. Calculate the signal-to-noise ratio for the top chan-
                                nel in a 24-channel FDM baseband signal, evaluated under test conditions for
                                which Table 9.1 applies. The emphasis improvement is 4 dB, noise weighting
                                improvement is 2.5 dB, and the peak/rms factor is 13.57 dB. The audio channel
                                bandwidth may be taken as 3.1 kHz.
                                Solution Given data: n   24; gdB   13.57; b   3.1 kHz; [P]   4; [W]   2.5;
                                [C/N]   25

                                From Eq. (9.17):
                                                            gdB
                                                       g 5 10  / 20  5 4.77
                                From Eq. (9.19):
                                                          s2114 log nd
                                                     L 5 10    / 20  5 1.683
                                From Table 9.1, for 24 channels ΔF rms   35 kHz, and using Eq. (9.20),
                                                         #  #
                                                    F   g    L     F rms  > 281 kHz
                                Assuming that the baseband spectrum is as shown in Fig. 9.4a, the top frequency is

                                                         f m   108 kHz
                                and Carson’s rule gives
                                                   B IF   2s F   f m d   778 kHz
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