Page 140 - Schaum's Outline of Differential Equations
P. 140

CHAP.  14]            SECOND-ORDER  LINEAR DIFFERENTIAL  EQUATIONS                    123



                  Substituting the given values into Eq. (14.7), we obtain the homogeneous  equation  [since E(t) = 12, dEldt  = 0]




               The roots of the associated  characteristic  equation are A,j = -10  +  10; and X 2 = -10  -  10;; hence,  this is an example
               of a free underdamped  system for the current. The  solution is


               The initial conditions are 7(0) = 0 and, from  Eq.  (14.8),





                                                                          10
               Applying  these  conditions  to  (7), we  obtain  c l = 0  and  c 2 =y;  thus,  I = ^e '  sinlOf,  which  is  completely
               transient.

         14.14.  Solve Problem  14.13 by first finding  the charge on the capacitor.
                  We  first  solve  for  the  charge  q and  then  use  7 = dqldt  to  obtain  the  current.  Substituting the  values  given in
               Problem  14.13 into Eq. (14.5),  we have  q + 20q + 200q = 24,  which represents  a forced  system for the charge,  in
               contrast  to the  free damped  system  obtained  in Problem  14.3 for  the  current. Using the  method  of undetermined
               coefficients  to find  a particular solution, we obtain  the general solution



               Initial conditions for the charge  are q(0)  = 0 and  q(0)  = 0; applying them, we obtain  Cj = c 2 = -3/25. Therefore,






               and

               as before.
                  Note that although the current is completely transient, the charge on the capacitor  is the sum of both transient
               and steady-state terms.

         14.15.  An RCL circuit connected in series has a resistance of 5 ohms, an inductance of 0.05 henry, a capacitor
                       4
               of 4 X 10~  farad, and an applied alternating emf of 200 cos  100? volts. Find an expression for the current
               flowing through this circuit if the initial current and the initial charge on the capacitor  are both zero.
                  Here RIL = 5/0.05 = 100, 1/(LC) = 1/[0.05(4 X 10^)] = 50,000, and




               so Eq.  (14.7)  becomes



               The  roots  of  its  characteristic  equation  are  -50  + 50Vl9i,  hence  the  solution  to  the  associated  homogeneous
               problem is



               Using the method  of undetermined coefficients, we find  a particular solution to be
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