Page 331 - Schaum's Outline of Differential Equations
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314                     SECOND-ORDER BOUNDARY-VALUE    PROBLEMS                  [CHAP.  32





                     positive.  To satisfy  the boundary  conditions,  B = 0 and either A = 0 or sinv^- = 0. This  last  equation  is
                     equivalent  to v^- = njt  where  n= 1, 2, 3, ....  The choice A = 0 results in the trivial  solution; the choic
                     V^- =  nn  results in the nontrivial  solution y n = A n  sin mtx.  Here the notation A n  signifies  that the arbitrary
                     constant A n  can be different  for different  values of n.
                  Collecting  the results of all three cases, we conclude  that the eigenvalues are X n = if  if  and the  corresponding
               eigenfunctions arey n = A n  sin nnx, for n= 1,2,3, ....

         32.11.  Find  the eigenvalues  and eigenfunctions of


                  As  in Problem  32.10, the cases  X = 0,  X < 0, and  X > 0 must be considered  separately.
               A, = 0:  The  solution is y = Cj + c 2x. Applying the boundary conditions, we obtain Cj = c 2 = 0; hence y = 0.

               K<0:  The solution is y  = c^e  + C 2e~  ,  where -X and  •J-'X.  are positive. Applying the boundary conditions,
                     we obtain




                     which admits only the solution c l = c 2 = 0; hence y = 0.
               A,>0:  The  solution  is  y = A sin •y'kx  + BcasyJix.  Applying the  boundary  conditions,  we  obtain  B = 0 and
                     A^J'k  cos V^- 7f  = 0. For  6 > 0, cos  6 = 0 if and  only  if  6 is a positive odd multiple of  n!2;  that is,  when
                     9  = (2n  — 1)(7T / 2) = (n  — \)n, where  n=  1, 2,3, ....  Therefore,  to  satisfy  the boundary conditions,

                     must  have B = 0 and either A = 0 or  cos V^- n  = 0. This last equation  is equivalent to  v^- = n — j. Th
                     choice  A = 0  results  in  the  trivial  solution;  the  choice  V^-  = n ~\  results  in  the  nontrivial  solution
                     y n = A n sin(«-|)j:.

                  Collecting  all three cases, we conclude  that the eigenvalues are  'k n  = (n  — -j)  and  the corresponding  eigen-
               functions  are y n  = A n sin (n  — j")x,  where n=l,2,3, ....


         32.12.  Show that the boundary-value problem  given in Problem  32.10 is a Sturm-Liouville problem.
                  It  has  form  (32.6)  with p(x)  = 1, q(x) = 0,  and  w(x)  = 1. Here  both p(x)  and  w(x)  are  positive and  continuous
               everywhere,  in particular on  [0,  1].

         32.13.  Determine  whether the boundary-value  problem



               is a Sturm-Liouville problem.
                                  2
                                                x
                  Here/>(X) =x,  q(x) =x + 1, and  w(x)  = e .  Since bo\hp(x)  and  q(x)  are continuous and positive on  [1, 2],  the
               interval  of interest, the boundary problem  is a Sturm-Liouville  problem.
         32.14.  Determine  which of the following differential equations with the boundary conditions y(0)  = 0, /(I) = 0
               form  Sturm-Liouville problems:








                                                                      x
               (a)  The  equation  can  be  rewritten  as  (e*y')'  + 'ky  = 0;  hence  p(x)  = e ,  q(x) = 0,  and  w(x)  = 1.  This  is  a
                   Sturm-Liouville  problem.
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