Page 24 - Schaum's Outline of Theory and Problems of Applied Physics
P. 24

CHAP. 1]                               USEFUL MATH                                      9



                                                 Table 1-1

              Prefix   Power   Abbreviation  Pronunciation              Example

              pico-   10 −12       p         PEE · koh   1pf = 1 picofarad = 10 −12  farad
              nano-   10 −9        n         NAN · oh    1ns = 1 nanosecond = 10 −9  second
              micro-  10 −6        µ         MY · crow   1 µA = 1 microampere = 10 −6  ampere
              milli-  10 −3        m         MILL · ee   1mH = 1 millihenry = 10 −3  henry
              centi-  10 −2        c         SEN · tee   1cm = 1 centimeter = 10 −2  meter
                                                                           2
              hecto-  10 2         h         HEK · toe   1hL = 1 hectoliter = 10 liters
                                                                          3
              kilo-   10 3         k         KILL · oh   1kg = 1 kilogram = 10 grams
                                                                            6
              mega-   10 6         M         MEG · ah    1MW = 1 megawatt = 10 watts
                                                                                 9
              giga-   10 9         G         GEE · gah   1 GeV = 1 gigaelectronvolt = 10 electronvolts
                                                                          12
              tera-   10 12        T         TER · ah    1TJ = 1 terajoule = 10 joules

        SOLVED PROBLEM 1.21
              Rome is 1440 km by road from Paris. How far is this in miles?

                  Since 1 km = 0.621 mi,

                                                             mi
                                       1440 km = (1440  km) 0.621  = 894 mi

                                                             km
        SOLVED PROBLEM 1.22
              A man is 6 ft 2 in. tall. How many centimeters is this?
                  Since 1 ft = 12 in. and 1 in. = 2.54 cm,

                                                                   cm
                                 6ft2in. = [(6)(12) + 2] in. = (74  in.) 2.54  = 188 cm
                                                                    in.
        SOLVED PROBLEM 1.23
                                             2
              How many square feet are there in 1 m ?
                  Since 1 m = 3.28 ft,
                                                     2
                                                  ft              ft
                                                                   2
                                                           2
                                    2
                                           2
                                  1m = (1m ) 3.28    = (1  ) 10.76   = 10.76 ft 2
                                                         m

                                                 m               m 2
        SOLVED PROBLEM 1.24
              Express a velocity of 60 mi/h in feet per second.
                  There are 5280 ft in 1 mi and 3600 s in 1 h, so

                                      mi       mi       ft      1         ft
                                    60   = 60       5280              = 88

                                       h         h      mi   3600 s/h     s

        SOLVED PROBLEM 1.25
              The unit of electric charge, symbol Q, is the coulomb (abbreviated C); the unit of voltage, symbol V, is
              the volt (V); and the unit of capacitance, symbol C, is the farad (F). When the voltage across a capacitor
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