Page 74 - Schaum's Outline of Theory and Problems of Applied Physics
P. 74

CHAP. 5]                             LAWS OF MOTION                                    59




                                                         Reaction force of
                                                         table on book


                                                         Force of book
                                                         on table




                                                  Reaction forces of
                                                   floor on table

                                                   Forces of table
                                                     on floor
                                                     Fig. 5-5


        SOLVED PROBLEM 5.21
              In the process of walking, what force makes a person move forward?

                  The person’s foot exerts a backward force on the ground; the forward reaction force of the ground on the foot
              produces the forward motion.

        SOLVED PROBLEM 5.22

              A 2-kg block A and a 3-kg block B are in contact on a frictionless table, as in Fig. 5-6. A horizontal force
              of 10 N is applied to A. Find the force with which B resists the pressure of A on it.










                                                     Fig. 5-6


                  The blocks have the same acceleration of
                                                F        10 N
                                         a =        =           = 2 m/s 2
                                             m A + m B  2kg + 3kg
              To give B this acceleration, the force that A exerts on B must be F AB = m B a. The reaction force F BA has the same
              magnitude but the opposite direction, so
                                                                   2
                                     F BA =−F AB =−m B a =−(3kg)(2 m/s ) =−6N


        APPARENT WEIGHT

        The actual weight of a body is the gravitational force that acts on it. The body’s apparentweight is the force the
        body exerts on whatever it rests on. Apparent weight can be thought of as the reading on a scale a body is placed
        on. Figure 5-7 shows a woman whose actual weight is 700 N who is standing on a scale in an elevator. When
        the elevator’s upward acceleration is a, the magnitude of the upward force F on her is the sum of her actual
        weight mg and the force ma that is accelerating her upward, so F = mg + ma. Her apparent weight w app is the
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