Page 339 - Schaum's Outline of Theory and Problems of Signals and Systems
P. 339

FOURIER ANALYSIS OF DISCRETE-TIME SIGNALS AND SYSTEMS  [CHAP. 6




                 and




           FREQUENCY RESPONSE

           6.31.  A causal discrete-time  LTI system is described by

                                         y[n] - +y[n - 11 + $y[n - 21  =x[n]                 (6.143)

                 where x[n] and  y[n] are the input and output of  the system, respectively (Prob. 4.32).
                 (a)  Determine the frequency response  H(n) of  the system.
                 (b)  Find the impulse response  h[n] of  the system.
                 (a)  Taking the Fourier transform  of  Eq. (6.1431, we obtain

                                          Y(R) - ie-'"~(fl) + ;e-j2'y (a) =X(R)
                      or
                                              (1 - ie-ifl  + Le  -j 2n)Y(R) = X(R)

                      Thus,






                 (6)  Using partial-fraction  expansions, we have
                                                     1           -     2    -     1
                                                                 -
                                   H(R) = (1 -          -  I       1  - Ie-in   1  - Le-in
                                                                       2
                      Taking the inverse Fourier transform  of  H(fl), we obtain
                                                 h[n] = [2(iln - (f)"]u[n]

                      which is the same result obtained in  Prob. 4.32(6).


           6.32.  Consider a discrete-time LTI system described by

                                         y[n] - ;y[n - 11 =x[n] + ix[n - 11

                 (a)  Determine the frequency response  H(n) of  the system.
                 (b)  Find  the impulse response h[n] of  the system.
                 (c)  Determine  its response  y[n] to the input
                                                                 iT
                                                      ~[n] cos-n
                                                           =
                                                                 2
                 (a)  Taking the Fourier transform  of  Eq. (6.1441, we obtain

                                          Y(R) - ie-jnY(R) =X(R) + ;e-jnx(R)
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