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CHAP. 71 STATE SPACE ANALYSIS
7.38. Consider the system in Prob. 7.32.
(a) Is the system controllable?
(6) Is the system observable?
(a) From the result from Prob. 7.32 we have
Now
and by Eq. (7.120) the controllability matrix is
and IM,I = - 4 # 0. Thus, its rank is 2 and hence the system is controllable.
(b) Similarly,
and by Eq. (7.123) the observability matrix is
and IMol = 0. Thus, its rank is less than 2 and hence the system is not observable.
Note from the result from Prob. 7.32(b) that the system function H(z) has pole-zero
cancellation. If H(z) has pole-zero cancellation, then the system cannot be both control-
lable and observable.
SOLUTIONS OF STATE EQUATIONS FOR CONTINUOUS-TIME LTI SYSTEMS
7.39. Find eA' for
using the Cayley-Hamilton theorem method.
First, we find the characteristic polynomial c(A) of A.
=A'+ 5A +6 = (A + 2)(A + 3)
Thus, the eigenvalues of A are A, = - 2 and A, = - 3. Hence, by Eqs. (7.66) and (7.67) we have