Page 209 - Semiconductor For Micro- and Nanotechnology An Introduction For Engineers
P. 209

Transport Theory
                                                       ,,
                                                     (
                                 ∂ f E k() x t,,(  )  δf kx t) µ    ∂ µ      ∂    (6.30)
                                                      ∂
                                                          ∂
                                                                
                                    0
                             =  – τ-------------------------------------  –  E –  µ T  ------ +  vF –  ------ –  E –  µ T 
                                                                        -------------------
                                                 ------------------- –
                                      ∂ E          T   t ∂  t ∂    ∂ x   T  ∂ x
                             We restrict the situation to a stationary analysis, where the time deriva-
                                                                            F
                             tives in (6.30) vanish. Let us assume that the external force   is given by
                             an electric field  E  , which itself can be expressed as the gradient of an
                             electrostatic potential (see (4.34)). The force acting on an electron is then
                             F =  – qE =  q∇ψ  . Note that the minus sign is due to its negative
                                                                           µ
                             charge. This allows us to combine the chemical potential   and the elec-
                                           ψ
                             trostatic potential   into one term forming the electrochemical potential
                                                        –
                Electro-                          η =  µ qψ                       (6.31)
                chemical
                Potential    Then the current densities become
                                                     f ∂  0   ∂ η  E –  µ T 
                                                                   ∂
                                                 ∫
                                                                       3
                Current               j xt,(  ) =  – τ v--------v – ------ –  ------------------- d k  (6.32)
                                                                    x
                                                     E 
                                       n
                                                                   ∂
                                                    ∂
                                                          ∂
                                                                T
                Density                                    x
                                                 V k
                             and
                                                      f ∂  0   ∂ η  E –  µ T 
                                                                   ∂
                                                ∫
                                                                        3
                Energy               j xt,(  ) =  – τ vE--------v – ------ –  ------------------- d k  (6.33)
                                      u              ∂ E   ∂ x  T  ∂ x
                Current
                                                V k
                Density
                             By a simple manipulation we ca see that the latter consists of two terms
                                                          f ∂  0   ∂ η  E –  µ T 
                                                                       ∂
                                                ∫
                                  (
                                    ,
                                                  (
                                                                            3
                                 j xt) =  µ j – τ v E –  µ)--------v – ------ –  ------------------- d k
                                                                        x
                                                          E 
                                 u
                                            n
                                                                       ∂
                                                         ∂
                                                              ∂
                                                                    T
                                                               x
                                               V k                                (6.34)
                                                                               
                                                             j
                                                              Q
                             With (6.34) we see that the current density consists of two parts: one that
                             is due to particle transport through spatial regions µ j   and a second that
                                                                        n
                             is due to heat transport  j  . Since the first part of the energy current is
                                                 Q
                             proportional to the particle current, in the following we focus on  j   and
                                                                                  Q
                             j  . Both current densities suggest a general structure of the form
                              n
                206          Semiconductors for Micro and Nanosystem Technology
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