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The K values are used along with the stoichiometric equations which state the mole fractions in liquid and
                    vapor phases must sum to 1.0.







                                                                                                                                (2-31)

                    where C is the number of components. Bubble-point and dew-point calculations are discussed in detail in
                    Section 5.4.

                    If only one component is present, then y = 1.0 and x = 1.0. This implies that K = y/x = 1.0. This gives a
                                                                                                            i
                    simple way of determining the boiling temperature of a pure compound at any pressure. For example, if
                    we wish to find the boiling point of isobutane at p = 150 kPa, we set our straightedge on p = 150 and at
                    1.0 on the isobutane scale on Figure 2-11. Then read T = –1.5°C as the boiling point. Alternatively, Eq.
                    (2-30) with values from Table 2-3 can be solved for T. This gives T = 488.68°R or –1.6°C.

                    For ideal systems Raoult’s law holds. Raoult’s law states that the partial pressure of a component is
                    equal to its vapor pressure multiplied by its mole fraction in the liquid. Thus,




                                                                                                                               (2-32a)

                    where vapor pressure (VP) depends on temperature. By Dalton’s law of partial pressures,




                                                                                                                               (2-32b)

                    Combining these equations,




                                                                                                                               (2-32c)
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