Page 546 - Standard Handbook Petroleum Natural Gas Engineering VOLUME2
P. 546
500 Production
24. Determine the liquid holdup:
v,-vq-vrL+[(v,-vq-v.&)*+4vs vrL]o.5
H, =
2v.
1.933- 4.08- 2.147+ I( 1.933- 4.08 - 2.147)' + 4( 1.933)( 2. 147)Ia5
= 0.42O4= 0.42
This value can be checked
Vw 4.08 - 2.147
=
v, = - 5 = - - 1.923
1-H, HL 1-0.42 0.42
25. Determine the liquid Reynolds number:
1,488~47.6~2.147~0.16625 60,773
=
(NbL =
0.416
26. Determine the friction gradient according to the flow region.
a) For Region I and I1
where f, = (fJ- f *
f,
fi is found in Figure 6-65 and f, is found in Figure 6-66.
The abscissa must be determined in Figure 6-66 and is fiRNy
where R = .%
v.&
f5 = 1 + f,(R/50)0.5
The friction factor f, is valid in Regions I and II and covers heading
also. It is good from zero NLv and N, up to the limit given by NP =
50 + 36 N,.
