Page 544 - Standard Handbook Petroleum Natural Gas Engineering VOLUME2

498 Production

vrL =
1 + WOR 1 + WOR

- - 8640qO. 5*61(480) 0217) [1.495(1.o)+l.o(o)] 1+0 = 2.147ft/s

17. Find the liquid velocity number:

v4
N, = 1.938 vL( %) = 1.938(2.147)( $r = 4.75

18. Find the superficial gas velocity:

1
qL GLR-R' l+WOR )I(=)( 14.7 Tayg
(
vsg = ' 86, 400Ap 520)(%)

- - qL[ GLR - '.( 1 + i0R)lBg
86, 400Ap
3,393-947.3 -
- - ( 0)]14.7 x 550(0. 72) = 4.08 ft/s
86,400(0.0217) 1719.5 x 520

19. Find the gas velocity number:

v4
=
N, = 1.938 v%( %) = 1.938~ 4.08( gr 9.03

20. Find the pipe diameter number:

a5
N, = 120.9d( 2)"" l20.9( -)( 995 18) = 26.2
47.6
=
1
21. Select the proper flow regime from Figure 6-61:
NBV = 9.03
N, = 4.75

These numbers fall in Region 11; see Figure 6-61.