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QUANTUM CHEMISTRY IN FRONT OF SYMMETRY BREAKINGS                       111








                       where a and b are the   atomic  orbitals of the carbon atoms  of  The  resonance
                       between the two VB forms   and    is  the interatomic  exchange  integral Kab.  The
                       repulsion between the two   groups tends to rotate the bond, and to put the a and b
                       orbitals in perpendicular orbitals. Then the Kab integral becomes very weak, and we have
                       again a weak resonance between two VB components. But these two forms tend to polarize
                       the  frame  in  two  opposite directions. The electronic  relaxation energy is  large and
                       prevails on the resonance. So that for highly twisted ethylene the singlet closed shell HF
                       function will be symmetry-broken and will give two   and         solutions,

                       polarized. Allowing then the   group to  pyrimidalize  leads to a  stable
                       structure. This phenomenon, discovered by Salem et al.  [34], has given raise to a great
                       interest in the early seventies under the name of "sudden polarization" but its suddeness has
                       been questionned when the potential energy  surface has been  more extensively  studied
                       [35].

                       2.6.   DENSITY FUNCTIONAL AND SYMMETRY BREAKING

                       As long as it maintains the single determinant picture, the density functional function does
                       not dissociate properly the chemical bonds, and is thus the subject of symmetry breaking at
                       large interatomic distances. We may equivalently say that the correlation potential (i.e. the
                       difference between the exact exchange and the exchange correlation potential) diminishes
                       the electronic repulsion or that it increases the delocalization. Turning to the VB formulation
                       of  the HF  instability, this  implies  that the  symmetry breaking  will  occur at  larger
                       interatomic distances in DF calculations than in HF ones,


                       Then an interesting question would be : for molecules which present strong HF symmetry
                       breaking at equilibrium distance, such as   Be2 or cyclic   (and eventually  are
                       the symmetry-adapted LDF solutions stable at these distances ? If they are not, one will
                       face an embarrassing problem  ;  since the calculated dissociation energies, are already
                       correct when using the SA, solution at short distance and the separated atoms energies what
                       should one think of the lower UHF solutions ? Let remember that most LDF calculations
                       on organometallic systems or metallic clusters are LSD (Local Spin Density) calculations
                       (i.e. performed in  the UHF formalism). Why should one accept the  symmetry (closed
                       shell) constraint in some cases and not in others ?
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