Page 229 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 229

216                                      Lagrange’s Equation   Chap. 7


                                  A brief development of Lagrange’s equation is presented in Appendix E. We
                              now  demonstrate  the  use  of  Lagrange’s  equation  as  applied  to  some  simple
                              examples.
                              Example 7.3-1
                                  Using  Lagrange’s  method,  determine  the  equation  of motion  for  the  3-DOF  system
                                  shown  in  Fig.  7.3-1.
                              Solution:  The  kinetic  energy here  is  not  a function of   so that  the  term  dT/dq-  is zero.
                                  We  have the  following for the  kinetic and potential  energies:
                                                 T =  1    • ?  1 1    • 2  1 1    -2


                                                 T-
                                                                +  2W39 3
                                                U =  \k^qj +  {k2(q2 ~ Q\f +  'i^^iq^ ~ qzf
                                  and  T  for this problem is a function  of only q-  and  not of  q^.
                                       By substituting into Lagrange’s equation  for  /  =  1,
                                                     dT     .    d
                                                                 Tt
                                                     dU
                                                        = ^,<7,  -  ^ 2(^2  -   ii)
                                                     dq^
                                  and  the  first equation  is
                                                     W,<7,  +  (^,  +  ^2)91  -   ^2^2  = 0
                                       For  /  =  2, we  have
                                                     dT          d  I dT\
                                                     dq2
                                                     dU
                                                     ^    =   ^2(92  -   <?i)  -   ^3(^3  -   di)
                                  and the  second  equation becomes

                                                    ^ 2^2  ~  ^2^1   (^2  ■*"  ^3)^2  ~  ^3^3
                                       Similarly for  /  =  3,
                                                     dT

                                                     dq^  "^3^3  dt \ 5^3 )  “■ '” 3^3
                                                    ^    = ^3(^3  -  di)

                                  with the  third  equation
                                                            -  ^3^2  + ^3^3  = 0



                                  |V v v { ^ r ^ A A A A r Q - A A A A . Q    Figure 7.3-1.
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