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8.4 Two-Phase System with a Chemical Reaction   147


         The reactions in the system are represented as
                                      A,  + B,  = C,                     (8.4-2)

                                                                         (8.4-3)
                                                                         (8.4-4)
         Note  that  the  phase  transfer  is  treated  like  a  chemical  reaction.  When  the
         equilibrium  conditions  for  these  three  reactions  are  introduced  into  equation
         8.4-1, we obtain

         dG = - SdT+ VdP + PA&~A,  + ~ASdn,,qj + ~cdl~,c + (4,  - 4JdQ   (8.4-5)
         The  partial  derivative  of  the  Gibbs  energy  with  respect  to  the  amount  of  a
         component  yields  the  chemical  potential  of  a  species  (Beattie  and  Oppenheim,
         1979).

                                                                         (8.4-6)

         The criterion  for equilibrium  based  on G  is  dG < 0 at constant  7; P, nLAa, IZ,~,,
         nee,  and  Q.  Integration  of  equation  8.4-1  at  constant  values  of  the  intensive
         variables yields
                                   +
                        G = PAAA~ pAfinc4p  + Pc’,c  + (4~ 4JQ           (8.4-7)
                                                         -
             The Gibbs-Duhem equations for the two phases are
                          0 = - S,d T + I/,dP - ncA,dpAa - ncsadpc       (8.4-8)
                      0 = - S,dT+  I/;,dP - ncABdpA, - nCcBdpc - Qdq5,J   (8.4-9)
         where  4,  has  been  taken  equal  as  zero.  Since  there  are  six  variables  and  two
         equations, F  = 4, which  can  be  taken  to  be  7;  P, pAa, and  &.  The number of
         independent  intensive  variables  can  also  be  calculated  using  the  phase  rule:
         F  = C - p + 3 = 3 - 2 + 3 = 4, where  the  3 is for  7; P, and (PR. The number D
         of natural variables is given by D  = F + p  = 4 + 2 = 6.
             The equilibrium  expressions  for  reactions  8.4-2 to  8.4-4, which  are derived
         from the equilibrium conditions  using equation 8.3-8, are

                                 %a
                          K, =  ~    = exp[ - p:  - pl-  ,ui)/R T]      (8.4- 10)
                               ‘Aa‘Ba
                                 uc,
                          K  --      = exPC-(P:   - Pi - PWTI           (8.4-1 1)
                            ’ - uApaBp

                                                                        (8.4-12)

         The effect of  the electric potential cancels in a chemical reaction in a phase. Note
         that  uc,  and uCa are not independent  variables in  the  chemical  reaction  system.
         Substituting the equilibrium concentrations of C from equations 8.4-10 and 8.4-1 1
         in equation 8.4-12 yields

                                                                        (8.4- 13)


         or

                                                                        ( 8.4- 14)

         This shows how a chemical reaction can establish an electric potential  difference
         between phases. This potential difference can then be used to transport other ions
         between the phases  against their concentration gradients.
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