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280   Chapter 9  Thermal Conductivity and the Mechanisms  of Energy Transport

                                                                         3
       EXAMPLE  9.4-1      The density  of liquid  CC1  at 20°C and 1 atm is  1.595  g/cm , and its isothermal  compressibility
                                               4
                                                      1
                                                 6
                           {1/р){др/др)  is  90.7  X 10"  atm" . What  is its thermal conductivity?
     Prediction  of  the              т
      Thermal  Conductivity  SOLUTION
      of  a  Liquid
                           First compute
                                     dp         1               1        =  6.91  X 10  atm • cm /g
                                                                                  3
                                                                                           3
                                                                       6
                                           р(1/р)(др/др)  (1.595X90.7 X 1(Г )
                                     др 1т            т
                                                  9
                                                      2
                                                        2
                                         =  7.00  X 10  cm /s  (using Appendix  F)              (9.4-5)
                           Assuming  that C /C  = 1.0, we get  from  Eq. 9.4-4
                                         p  v
                                                                            4
                                                                 9
                                                v s  = V(l.0X7.00 X 10 )  = 8.37  X 10  cm/s    (9.4-6)
                           The molar volume  is  V  = M/p  = 153.84/1.595  = 96.5 cm /g-mole. Substitution  of  these  val-
                                                                         3
                           ues  in Eq. 9.4-3 gives
                                                       2/3
                                             =  2.S0(N/V) Kv,
                                                 /б.О23  x  10 V ,         16      4
                                                           23
                                                              /3
                                             =  2  8(          (1.3805  X 10" )(8.37X  10 )
                                                    0.965 X 10 2
                                                   ч
                                                           2
                                                      4
                                             =  1.10  x  10  (cm- )(erg/K)(cm/s)
                                             =  0.110W/m-K                                      (9.4-7)
                           The experimental value  given  in Table 9.1-2 is 0.103 W/m  •  K.
      §9«5  THERMAL CONDUCTIVITY OF SOLIDS
                           Thermal conductivities  of  solids  have  to be measured  experimentally,  since they depend
                           on  many  factors  that  are  difficult  to  measure  or  predict. 1  In  crystalline  materials,  the
                           phase  and  crystallite  size  are  important; in  amorphous  solids  the  degree  of  molecular
                           orientation  has  a  considerable  effect.  In  porous  solids,  the  thermal  conductivity  is
                           strongly  dependent  on  the  void  fraction,  the  pore  size,  and  the  fluid  contained  in  the
                           pores. A detailed  discussion  of thermal conductivity  of solids  has been given  by Jakob. 2
                               In general, metals are better heat conductors than nonmetals, and crystalline  materi-
                           als  conduct  heat  more  readily  than  amorphous  materials.  Dry  porous  solids  are  very
                           poor  heat conductors and  are therefore  excellent  for  thermal insulation. The conductivi-
                           ties  of  most pure  metals  decrease  with  increasing  temperature, whereas  the conductivi-
                           ties  of  nonmetals increase; alloys  show  intermediate behavior.  Perhaps  the most  useful
                           of the rules  of thumb is that thermal and electrical conductivity  go hand in hand.
                               For pure  metals, as  opposed  to alloys,  the thermal conductivity  к and  the  electrical
                           conductivity  k  are related approximately 3  as  follows:
                                       e
                                                            =  L = constant                     (9.5-1)
                                                        kJ
                           This is the  Wiedemann-Franz-Lorenz equation; this equation can also be explained  theoret-
                                                                                          9
                                                                                               2
                           ically  (see  Problem  9A.6).  The  "Lorenz number"  L is  about  22  to  29  X  1СГ  volt /K  2  for


                               1  A. Goldsmith, T. E. Waterman, and H. J. Hirschhorn, eds., Handbook of Thermophysical  Properties of
                           Solids, Macmillan, New  York  (1961).
                               2  M. Jakob, Heat Transfer, Vol.  1, Wiley, New York  (1949), Chapter 6. See also W. H. Rohsenow,
                           J. P. Hartnett, and  Y. I. Cho, eds., Handbook of Heat Transfer, McGraw-Hill, New  York  (1998).
                               3  G. Wiedemann and  R. Franz, Ann.  Phys.  u. Chemie, 89, 497-531  (1853); L. Lorenz, Poggendorff's
                           Annalen,  147,429-452  (1872).
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