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§10.3  Heat Conduction with a Nuclear Heat Source  297

                Rate  of heat out
                                                                 )
                                                              2
                                       {F)
                by  conduction         q \  Г+Дг  •  4тг(г  + Ar) 2  =  (4тгг ^^) | Г+Дг  (10.3-3)
                at г +  Ar
                Rate of thermal
                energy  produced                 S, • 4тгг 2  Ar                      (10.3-4)
                                                  ;
                by  nuclear  fission
                Substitution  of  these terms into the energy  balance  of  Eq.  10.1-1  gives, after  dividing  by
                4TT Ar and taking the limit as  Ar  —> 0

                                                                                    (10.3-5)

                Taking  the limit and introducing the expression  in Eq. 10.3-1 leads to

                                                                                    (10.3-6)

                The differential  equation  for  the heat flux q  in the cladding  is  of  the same  form  as  Eq.
                                                     ( C)
                                                     r
                10.3-6, except that there is no significant  source term:
                                                                                    (10.3-7)
                Integration  of these two equations gives


                                                                                    (10.3-8)
                                                              —
                                                с ( С )                             (10.3-9)
                                                 г  2
                in  which  C\ n  and  C  are  integration  constants. These  are  evaluated  by  means  of  the
                                  ( C)
                                  1
                boundary conditions:
                B.C. 1:                  at r  = 0,  q\  is not infinite            (10.3-10)
                                                     F)
                B.C. 2:                  at r  = R ,  q  = q\°                      (10.3-11)
                                                      { F)
                                                iF)
                                                       r
                Evaluation  of  the constants then leads  to
                                                  Ф       ъ А
                                            q  i F )  =  <                          (10.3-12)



                                                           R (F)3
                                             (С)                                   (10.3-13)
                                                       Л) г  2

                These  are  the heat  flux distributions  in  the fissionable  sphere  and  in  the  spherical-shell
                cladding.
                    Into  these  distributions  we  now  substitute  Fourier's  law  of  heat  conduction  (Eq.
                B.2-7):
                                              dT {F)
                                           UF)          L.  +  _  —                (10.3-14)
                                               dr
                                                                                   (10.3-15)
                                               dr
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