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Pr oject Considerations for Horizontal Dir ectional Drilling   225


          Pipe Collapse
          ASTM F1962 specifies that the effective applied pressure to be less
          than the collapse load as given by Eq. (5.14), but with a safety factor,
          such as 2-to-1. As applied to Eq. (5.23) for Mini-HDD applications,
          the requirement, therefore, corresponds to:
                   H (ft) ≤ 1000 hour water head (Table 5.1)/6.0   (5.25)

             Such additional margin is intended to account for loads or degrad-
          ing effects not previously directly considered, such as a possibly
          extended period for the drilling fluid/slurry to thicken and provide
          the anticipated lateral support.
             This procedure is considered reasonably conservative for Mini-
          HDD installations for drilling under roads or most other obstacles.
          For river or creek crossings, in which the soil loads may be influenced
          by the overlying water, additional considerations may be warranted,
          such as discussed by Petroff (2006). For such cases, it may be desired
          to use a greater safety factor or a longer term collapse strength.
          5.5.4 Design Example
          The appropriate wall thickness of an HDPE pipe, for a given diame-
          ter, may be conveniently determined by the application of Eqs. (5.24)
          and (5.25). As an example, consider the feasibility of installing a 4-in.
          HDPE pipe of DR 11 rating, for a relatively long 600 ft Mini-HDD
          route, including one deliberate 90° planar bend, and placed at a rela-
          tively large depth of 30 ft.
             The following physical properties apply to the HDPE pipe and
          specified route:
                             L   = 600 ft
                              bore
                               D = 4.50 in.
                              w  = 2.3 lb/ft
                                a
                               H = 30 ft
             Based upon these values, the following values may be directly
          calculated:
                       n  = 1.0 (one deliberate 90° bend)
                        1
                       n  = L   (ft)/500 ft
                        2   bore
                         = 600 ft/500 ft
                         = 1.2 (additional equivalent 90° bend)
                        n = n  + n
                            1   2
                         = 1.0 + 1.2
                         = 2.2
                                2
                       w  = 0.5 · D  – w  (lb/ft)
                        b           a
                                   2
                         = 0.5· (4.50)  – 2.3 (lb/ft)
                         = 7.8 lb/ft
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