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104
                                                   Quantities of Water Demand
                                          Chapter 4
                                      EXAMPLE 4.6 ESTIMATION OF THE RATIOS OF MAXIMUM, WEEK, DAY, AND HOUR DEMAND IN THE
                                      ABSENCE OF ACTUAL WATER DEMAND DATA
                                      Determine the “percent of annual average water demand” for (a) daily average in maximum month; (b) daily average in maximum
                                      week; (c) maximum day in a year; and (d) peak hour within a day assuming the peak hour demand is distributed over 2 hours, all
                                      using the following equation:
                                                                                P = 180 (t)
                                      where P = percent of the annual average day water demand for time t and t = time in days, which varies from 2/24 to 365.
                                      Solution:
                                         a. For the daily average in maximum month, t = 30 days.  −0.1                         (4.23)
                                             P = 180(t) −0.1  = 180(30) −0.1  = 180 × 0.7117 = 128.
                                             Daily average water demand in maximum month = 1.28 Q ave-day .
                                        b. For the daily average in maximum week, t = 7days.
                                             P = 180(t) −0.1  = 180(7) −0.1  = 180 × 0.8232 = 148.
                                             Daily average water demand in maximum week = 1.48 Q ave-day .
                                         c. For the maximum day in a year, t = 1day.


                                             P = 180(t) −0.1  = 180(1) −0.1  = 180 × 1 = 180.
                                             Maximum day water demand in a year = 1.8 Q  .
                                                                                 ave-day
                                        d. For the peak hour within a day assuming the peak hour demand is distributed over 2 hours, t = 2/24 days.


                                             P = 180(t) −0.1  = 180(2/24) −0.1  = 180 × 1.2821 = 231.
                                             Peak hour demand within a day = 2.31 Q ave-day .






                                    4.5 DEMAND AND DRAINAGE LOADS OF
                                    BUILDINGS

                                    The demand load of a building depends on the number
                                                                                          1. Demands for service sinks are ignored in calculating
                                    and kinds of fixtures and the probability of their simulta-
                                                                                             the total fixture demand.
                                    neous operation. Different fixtures are furnished with water
                                                                                          2. Demands of supply outlets, such as sill cocks, hose
                                    at different rates as a matter of convenience and purpose.
                                                                     3
                                    Expressed in cubic feet per minute (ft /min), or liter per  connections, and air conditioners, through which
                                                                                             water flows more or less continuously for a consid-
                                    second (L/s) for fixture units, these rates become whole
                                                                                             erable length of time, are added to the probable flow
                                    numbers of small size. Common demand rates are shown in
                                                                                             rather than the fixture demand.
                                    Table 4.15.
                                        It is quite unlikely that all fixtures in a building system  3. Fixtures supplied with both hot and cold water exert
                                    will draw water or discharge it at the same time. A probabil-  reduced demands on main hot-water and cold-water
                                    ity study of draft demands leads to the relationships plotted  branches (not fixture branches). An allowance of
                                    in Fig. 4.5. In practice, the values shown are modified as  three-fourths of the demand shown in Table 4.15 for
                                    follows:                                                 individual fixtures is suggested.
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