Page 88 - Wind Energy Handbook
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62                         AERODYNAMICS OF HORIZONTAL-AXIS WIND TURBINES


          The rate of change of axial momentum of the air passing through the swept annulus
          is

                                                       2
                            rU 1 (1   a)2ðrär2aU 1 ¼ 4ðrU a(1   a)rär          (3:47)
                                                       1
          The drop in wake pressure caused by wake rotation is equal to the increase in
          dynamic head, which is

                                          1        2
                                            r(2a9Ùr)
                                          2
          Therefore the additional axial force on the annulus is

                                        1        2
                                         r(2a9Ùr) 2ðrär
                                        2
          Thus

                   1    2                              2               2
                    rW Nc(C l cos ö þ C d sin ö)är ¼ 4ðr[U a(1   a) þ (a9Ùr) ]rär
                                                       1
                   2
          Simplifying,


                        W 2   c                                     2
                           N   (C l cos ö þ C d sin ö) ¼ 8ð(a(1   a) þ (a9ºì) )ì  (3:48)
                        U 2 1  R
          The element of axial rotor torque caused by aerodynamic forces on the blade
          elements is

                                            1
                                                 2
                      (äL sin ö   ä D cos ö)r ¼ rW Nc(C l sin ö   C d cos ö)rär  (3:49)
                                            2
          The rate of change of angular momentum of the air passing through the annulus is

                                                                   2
                         rU 1 (1   a)Ùr2a9r2ðrär ¼ 4ðrU 1 (Ùr)a9(1   a)r är
          Equating the two moments

                     1    2                                            2
                      rW Nc(C l sin ö   C d cos ö)rär ¼ 4ðrU 1 (Ùr)a9(1   a)r är  (3:50)
                     2
          Simplifying,


                           W 2   c                         2
                               N   (C l sin ö   C d cos ö) ¼ 8ðºì a9(1   a)   (3:50a)
                           U 2 1  R
          where the parameter ì ¼ r=R.
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