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276                               Chapter 7  Yielding and Fracture under Combined Stresses


            In the present chapter, failure criteria will be considered on the basis of values of stress. Their
            application involves calculating an effective value of stress that characterizes the combined stresses,
            and then this value is compared with the yield or fracture strength of the material. A given material
            may fail by either yielding or fracture, depending on its properties and the state of stress, so that, in
            general, the possibility of either event occurring first must be considered.

            7.1.1 Need for Failure Criteria
            The need for careful consideration of failure criteria is illustrated by the examples of Fig. 7.1. For
            these examples, the material is assumed to be a ductile engineering metal, the behavior of which
            approximates the ideal elastic, perfectly plastic case. A uniaxial tension test provides the elastic
            modulus E, and the yield strength σ o , as shown in (a). Now assume that a transverse compression
            of equal magnitude to the tension is also applied, as shown in (b). In this case, the tension σ y


                 (a)  y  σ y               (b)  y  σ y               (c)  y  σ y

                                                          σ                          σ
                                                           x                         x
                                 x                          x                         x
                                                      σ   − σ       z           σ  σ
               z                         z             x    y                    x  y


                 σ                         σ                         σ y
                  y        σ                y                                σ ≈  σ o
                                                                              y
                            o
                                                  σ ≈  σ /2
                                                   y   o                  E
                                                                         1 −  ν
                     E
                                                E
                                               1 + ν
                                  ε                         ε                         ε y
                 0                 y       0                 y       0

                                                           − σ
                                (d)  y  σ y                  y
                                                                        σ
                                                                        o
                                               σ
                                                x                E
                                                x              1 − 2ν
                                   σ
                                    z
                              z      σ  σ   σ   − p                          − ε  y
                                      x  y   z              0
            Figure 7.1 Yield strengths for a ductile metal under various states of stress: (a) uniaxial
            tension, (b) tension with transverse compression, (c) biaxial tension, and (d) hydrostatic
            compression.
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