Page 298 - Materials Chemistry, Second Edition
P. 298

VOC-Laden Air Treatment                                          281



           a solid waste. The heating value of an air stream containing organics can be
           determined by:

            Heatingvalue of an airstreamcontainingVOCs(in Btu/scf)
             =VOC’s heatingvalue (inBtu/lb)  × Mass concentrationofthe VOC(lb/scf)

                                                                          (7.15)
             We can divide the heating value of a waste air stream in Btu/scf by the
           density of the air to obtain the heating value in Btu/lb.

            Heatingvalue of an airstreamcontainingVOCs(in Btu/lb)
                =Heating value(in Btu/scf) Densityofthe airstream(lb/scf)÷  (7.16)

             The density of an air stream under the standard condition can be found as:

                                                     Molecularweight
                     Densityofanair stream (inlb/scf) =                   (7.17)
                                                           392
             Since air consists mainly of 21% oxygen (MW = 32) and 79% nitrogen (MW =
           28), people normally use 29 as the molecular weight of the air. Consequently,
           the density of the air is 0.0739 lb/scf (= 29/392). This value can also be used
           for VOC-laden air, provided the VOC concentrations are not extremely high.


           Example 7.7:   Estimate the Heating Value of an Air Stream
           Referring to the remediation project described in Example 7.1, a thermal oxi-
           dizer is also considered to treat the off-gas. Estimate the heating value of the
           air stream that contains 800 ppmV of xylene.

              Solution:
               (a)  Use the Dulong’s formula (Equation 7.14) to estimate the heating
                   value of pure xylene:
                   Molecular weight of xylene (C H (CH ) )  = 12 × 8 + 1 × 10 = 106
                                              6
                                                4
                                                     3 2
                   Weight percentage of C = (12 × 8) ÷ 106 = 90.57%
                   Weight percentage of H = (1 × 10) ÷ 106 = 9.43%
                                                           O 
                    Heatingvalue (inBtu/lb) = 145.4 C+ 620  H −  8   + 41 S
                                                              
                                                       
                                                                 0 
                                          = 145.4(90.57) + 620 9.43  −  + 41(0)
                                                           
                                                                   
                                                           
                                                                  8
                                          = 19,015
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