Page 300 - Materials Chemistry, Second Edition
P. 300

VOC-Laden Air Treatment                                          283



                       TABLE 7.2
                       The LEL and UEL of Some Organic Compounds in Air
                       Compounds         LEL (% volume)  UEL (% volume)
                       Methane              5.0           15.0
                       Ethane               3.0            3.0
                       Propane              2.1            9.5
                       n-Butane             1.8            8.4
                       n-Pentane            1.4            7.8
                       n-Hexane             1.2            7.4
                       n-Heptane            1.05           6.7
                       n-Octane             0.95           3.2
                       Ethylene             2.7           36
                       Propylene            2.4           11
                       1,3 Butadiene        2.0           12
                       Benzene              1.3            7.0
                       Toluene              1.2            7.1
                       Ethyl benzene        1.0            6.7
                       Xylenes              1.1            6.4
                       Methyl alcohol       6.7           36
                       Dimethyl ether       3.4           27
                       Acetaldehyde         4.0           36
                       Methyl ethyl ketone  1.9           10
                       Source:  [1].

           Example 7.8:   Determine the Heating Value of an
                        Air Stream at 25% of Its LEL
           An off-gas stream contains a high level of benzene. The heating value of ben-
           zene is 18,210 Btu/lb. Determine the heating value of an off-gas stream that
           corresponds to 25% of its LEL.

              Solution:
               (a)  From Table 7.2, the 100% LEL of benzene in air is 1.3% by volume.
                      Then, 25% of LEL  = (25%)(1.3%) = 0.325% by volume
                                       = 3,250 ppmV

                   Molecular weight of benzene (C H ) = 12 × 6 + 1 × 6 = 78
                                                  6
                                                6
                                                         3
                   Use Equation (7.8) to convert ppmV to lb/ft :
                                 78
                                                                °
                                                ×
                                                    −6
                        1ppmV  =    × 10 −6  = 0.199 10 lb/ft 3  at77F
                                 392
                       3,250 ppmV = (3,250)(0.199 × 10 ) = 6.47 × 10  lb/ft 3
                                                             −4
                                                  −6
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