Page 301 - Materials Chemistry, Second Edition
P. 301

284       Practical Design Calculations for Groundwater and Soil Remediation



               (b)  Use Equation (7.15) to determine the heating value of the off-gas:

                     Heatingvalue (inBtu/scf)
                         = 18,210 Btu/lb  × (6.47  × 10 −4  lb/scf)= 11.8 Btu/scf

               (c)  Use Equation (7.16) to convert the heating value into Btu/lb:

                   Heatingvalue of an airstreamcontainingbenzene (inBtu/lb)
                       = 11.8 Btu/scf  ÷ 0.0739 lb/scf =160Btu/lb

              Discussion:
              The calculated heating value, 11.8 Btu/scf or 160 Btu/lb, is similar to
                the value of 13 Btu/scf or 176 Btu/lb for 25% LELs of typical VOCs.

             When dilution is required, the volumetric flow rate of the dilution air can
           be found as [1]:


                                                  
                                    Q dilution =    H w  −  1   Q w     (7.18)
                                              H i  

           where
             Q dilution     =  required dilution air, scfm
             Q w     =  waste air stream to be treated, scfm
             H       =  heat content of the waste air stream, Btu/scf (or Btu/lb)
               w
             H       =   heat content of the desired influent entering the treatment sys-
               i
                       tem, Btu/scf (or Btu/lb)

           Example 7.9:   Determine the Requirement of the Dilution Air
           An off-gas stream (Q = 200 scfm) is to be treated by direct incineration. The
           heating value of the off-gas is 300 Btu/lb. The insurance policy limits the
           COC concentration in the influent air to the thermal oxidizer to ≤25% of its
           LEL. Determine the required dilution air flow rate.

              Solution:
              Use 176 Btu/lb as the heating value that corresponds to 25% LEL. The
                dilution air flow rate can be determined by using Equation (7.18) as:

                                 H          300  
                                                         =
                        Q dilution  =    w  − 1 Q w  =    − 1(200) 141 scfm
                                       
                                                    
                                 H i        176  
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