Page 158 - A First Course In Stochastic Models
P. 158

THE FLOW RATE EQUATION METHOD                  151

                In mathematical terms,

                                        p j  q jk =  p k   q kj .
                                    j∈A   k /∈A   k /∈A  j∈A
                The balance principle (4.2.9) enables us to write down a recursive equation for the
                p j when
                      I = {0, 1, . . . , N} and q ij = 0 for i ≥ 1 and j ≤ i − 2,

                where N ≤ ∞. Then, by taking A = {i, . . . , N} with i  = 0 and applying the
                balance principle (4.2.9), we get

                                         i−1   N

                                q i,i−1 p i =  p k  q kj ,  i = 1, . . . , N.  (4.2.10)
                                         k=0   j=i
                This recursive relation is used quite often in queueing applications; see Chapter 5.
                In queueing applications it is often the case that direct transitions from any state i
                are either to higher states or to the state i − 1 directly below state i. A recursive
                computation of the state probabilities is usually much faster than a computation by
                any other method. Also the recursion scheme (4.2.10) is numerically stable since
                it involves no subtractions.
                  Next we apply the flow rate equation method to the two examples discussed in
                the previous section.


                Example 4.1.1 (continued) Inventory control for an inflammable product
                In this example the equilibrium probability p j represents the long-run fraction of
                time that the stock in the tank equals j units. Assumptions 4.1.2 and 4.2.1 are
                trivially satisfied (e.g. take state Q as regeneration state r). Using the transition
                rate diagram in Figure 4.1.1 and equating the rate at which the process leaves state
                i to the rate at which the process enters state i, it follows that

                                  µp 0 = λp 1 ,
                                  λp j = λp j+1 ,  j = 1, 2, . . . , Q − 1,
                                 λp Q = µp 0 .

                These equilibrium equations together with the equation p 0 + p 1 + · · · + p Q = 1
                have a unique solution (in this special case an explicit solution can be given:
                p 0 = (1 + Qµ/λ) −1  and p 1 = · · · = p Q = (µ/λ)p 0 ). Next we can answer the
                questions posed earlier:
                                                               Q

                              the long-run average stock on hand =  jp j    (4.2.11)
                                                              j=0
                            the long-run fraction of demand that is lost = p 0 .  (4.2.12)
   153   154   155   156   157   158   159   160   161   162   163