Page 196 - A First Course In Stochastic Models
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THE ERLANG DELAY MODEL                     189

                1 and so p 0 = 1 − λ/µ. Hence we find the explicit solution
                                                i
                                    p i = (1 − ρ)ρ ,  i = 0, 1, . . .        (5.1.2)
                with ρ = λ/µ. In particular, 1 − p 0 = ρ and so ρ can be interpreted as the long-
                run fraction of time the server is busy. This explains why ρ is called the server
                utilization. Let

                       L q = the long-run average number of customers in queue
                (excluding any customer in service). The constant L q is given by

                                              ∞

                                         L q =   (j − 1)p j ,
                                              j=1
                as can be rigorously proved by assuming a cost at rate k whenever k customers are
                waiting in queue and applying Theorem 4.2.2. Substituting (5.1.2) into the formula
                for L q , we obtain
                                                  ρ 2
                                            L q =     ,
                                                 1 − ρ
                in agreement with the Pollaczek–Khintchine formula for the general M/G/1 queue.
                  To determine the waiting-time probabilities we need the so-called customer-
                average probabilities

                          π j = the long-run fraction of customers who find j other
                              customers present upon arrival, j = 0, 1, . . . .

                In the M/M/1 case the customer-average probabilities π j are identical to the
                time-average probabilities p j , that is,

                                       π j = p j,  j = 0, 1, . . . .         (5.1.3)
                This identity can be seen from the PASTA property. Alternatively, the identity can
                be proved by noting that in a continuous-time Markov chain, p j q jk represents the
                long-run average number of transitions from state j to state k ( = j) per time unit.
                Thus in the M/M/1 case the long-run average number of transitions from state
                j to state j + 1 per time unit equals λp j . In other words, the long-run average
                number of arrivals per time unit finding j other customers present equals λp j .
                Dividing λp j by the average arrival rate λ yields the customer-average probability
                π j . The probability distribution {π j } is the equilibrium distribution of the embedded
                Markov chain describing the number of customers present just before the arrival
                epochs of customers. This probability distribution enables us to find the steady-state
                waiting-time probabilities under the assumption of service in order of arrival. Let

                                  W q (x) = lim P {D n ≤ x},  x ≥ 0,         (5.1.4)
                                          n→∞
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