Page 45 - A Practical Companion to Reservoir Stimulation
P. 45

PRACTICAL COMPANION TO RESERVOIR STIMULATION




            EXAMPLE C-4
                                                                 and in oilfield units,
            Friction Pressure Drop Calculation
                                                                                 5.2 x  IO-'ffpLv  2
            Calculate the pressure drop per  1000 ft of  vertical tubing,   APf  =                          (C- 16)
            with  a  3.5-in. outside diameter, for  a polymer  solution at               d
            100°F. The rheological properties, n'  and K;;,,., are 0.39 and   where the Ap, is the pressure in pounds per square inch.
            4.5 x  lo-* Ibf-sec"'/ft*, respectively. Perform this calculation   If NRe is greater than 2100, the flow is turbulent and the
            for a range of injection rates up to 100 BPM. The fluid density   Fanning friction factor is given by
            is 60 Ib/ft3. Plot the results on log-log paper.
                                                                                                            (C-17)
            Solution
            (Ref. Section 5-2.3 and a fluid mechanics textbook)
            To calculate the friction pressure drop for any type flow, the   where
            Reynold's numbers must first be calculated. For a power law            log n'  + 2.5
            fluid this is given by                                             c=      50                   (C- 18)

                                                                 and

                                                                                   1.4 - log n'
                                                                               b=                           (C- 19)
                                                                                        7
              While Eq. C-10 is for consistent units, for oilfield units it
            becomes                                              The calculation  of  the pressure drop is then  given by
                                                                 Eq. C-16.
                                                                   A sample calculation is performed with q = 20 BPM.
                              0.249pv""'d"'
                      NRe  =                                       From Eq. C- 13 (and remembering that for OD = 3.5 in. the
                             961l'K (  ; -  '          (C-11)    ID z 3 in.), the velocity is
                                   1

                                   '
                                    "
                                    )
                                   I
                                                                                    20
            where p is in  Ib/ft',  v  is  in  ft/sec, d is in  in.,  and K'  is in   v  =  17.17 - = 3.81 ft/~e~.   (C-20)
            lbf-sec"'/ft*.                                                          3=
              The velocity is given by the obvious:                From Eq. C- 1 I, the Reynold's number is then calculated:
                                                       (C- 12)               (0.249) (60) (38.1)1'61(3"'39)
                                                                      NRe  =
                                                                            (96°,39) (4.5 x  lo-*) ( 1.39)0.39
            and in oilfield units,
                                                                          = 2.6  x  lo4.                    (C-21)
                                     4
                            v  =  17.17-,              (C- 13)     Therefore, the flow is turbulent.
                                     d2
                                                                   From Eqs. C- 17, C- 18 and C- 19, the friction factor is equal
            where q is barrels per minute.                       to 0.003, and from Eq. C- 16,
              If the NRe is less than 2100, laminar flow is in effect, and in
            such case the Fanning friction factor is                     (5.2 x    (0.003) (60) (1000) (38.1)'
                                                                  APf  =
                                   16                                                    3
                                                       (C- 14)
                             fr.  =  ->                                = 453 psi.                           (C-22)
                                  NRe
            leading to the classic pressure drop resulting from friction   Figure C-3 is a plot of the expected pressure drops. Clearly,
                                                                 the laminar and turbulent flow regimes are indicated by the
                                 2fr. PLVL                       sharp  bend  in  the  results.  These  values  are  likely  to  be
                          Ap+ =                        (C- 15)
                                    d                            significantly  lower  in  an  actual  operation  because  of  the
                                                                 liberal use of friction reducing agents.







            C- 6
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