Page 79 - Advanced Design Examples of Seismic Retrofit of Structures
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Example of a Two-Story Unreinforced Masonry Building Chapter  2 71


                                               K y X
                                                                       (2.21)
                                T xy ¼ M x   X    X
                                               2
                                            K x Y +  K y X 2
                                               K x Y
                                                                       (2.22)
                                T yx ¼ M y   X    X
                                               2
                                            K x Y +  K y X 2
                                               K y X
                                                                       (2.23)
                                T yy ¼ M y   X    X
                                               2
                                            K x Y +  K y X 2
             where:
                The calculations of shear force demand due to torsion for Wall#1 are as
             follows:
                                      2,986,473  0 8:92Þ
                                                 ð
                       T xx ¼ 2,375,496                  ¼ 342kg
                                         184,952,682,631
                                          T xy ¼ 0
                                                ð
                                     2,986,473  0 8:92Þ
                        T yx ¼ 625,852                  ¼ 902kg
                                        184,952,682,631
                                          T yy ¼ 0
                The generated demand force in each wall depends on the relative stiffness of
             that particular wall with respect to that of the other walls in that story which are
             parallel to this wall. The participation factor of each wall in masonry buildings
             with rigid diaphragm from the shear force demand is calculated according to
             Eq. (2.24).
                                              K i
                                       PF ¼ X n                        (2.24)
                                                K i
                                              i¼1
             where:
                K i is the wall’s stiffness. The walls’ participation factors and also demand
             forces are presented in Appendix-A Table A-C-2-5 and Table A-C-2-6,
             respectively.
                As an example, the generated demand forces in Wall#1 are determined as
             follows:
                                       2,986,473
                                 PF ¼            ¼ 0:39%
                                      760,987,984
                                      f U i ¼ PF F U
                               f UD 1 ¼ 0:39% 2156 ¼ 8:4 Ton
                                f UF 1 ¼ 0:39% 765 ¼ 3:0 Ton

                               Q UD ¼ Max f UD , f UD + T xx + T yx
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