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     15.3 Bessel Functions  553
                                                           0.3
                                                           0.2
                                                           0.1
                                                            0
                                                               0     5     10     15     20     25
                                                                               x
                                                          –0.1
                                                          –0.2
                                                          FIGURE 15.10 Interlacing lemma for J 7 (x), J 8 (x),
                                                          and J 9 (x).
                                        can be written as
                                                                            
      2
                                                                                  ν
                                                                   xy + y + λx −     y = 0
                                                                                  x
                                        which is the Sturm-Liouville equation
                                                                          
       2
                                                                                ν
                                                                    (xy ) + λx −    y = 0
                                                                                 x
                                                                             2
                                        on (0,1) with r(x) = p(x) = x and q(x) =−ν /x. From equation (15.8) with a = 0, c = 1 and
                                                                                             √
                                            2
                                        λ = b , solutions that are bounded on (0,1) are multiples of J ν  λx . Further, for solutions
                                                                                   √
                                        satisfying the boundary condition y(1) = 0, we need  λ to be a positive zero of J ν (x). Denote
                                        these positive zeros as j k , ordered so that
                                                                     0 < j 1 < j 2 < j 3 < ··· .
                                                            2
                                        Then the numbers λ n = j are eigenvalues of this problem, with eigenfunctions J ν ( j n x). Notice
                                                            n
                                        that ν is fixed here (occurring in the differential equation), so these eigenfunctions are all written
                                        in terms of the same Bessel function J ν .Itis j n that changes to form the eigenfunctions J ν ( j n x).
                                           These eigenfunctions are orthogonal on (0,1) with weight function p(x) = x. This means
                                        that
                                                                   	  1
                                                                      xJ ν ( j n x)J ν ( j m x)dx = 0
                                                                    0
                                        if n  = m.
                                           If f is piecewise smooth on (0,1), then we can write the eigenfunction expansion
                                                                          ∞
                                                                            c n J ν ( j n x)                   (15.27)
                                                                         n=1
                                        in which
                                                                           1
                                                                         0  xf (x)J ν ( j n x)dx
                                                                    c n =               .                      (15.28)
                                                                             1
                                                                                   2
                                                                            x(J ν (x)) dx
                                                                          0
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                                   October 14, 2010  15:20  THM/NEIL   Page-553        27410_15_ch15_p505-562





