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656 CHAPTER 18 The Potential Equation
z
ϕ
ρ
y
θ
x
FIGURE 18.3 Spher-
ical coordinates.
Assuming symmetry of the temperature function about the z-axis, the solution is inde-
pendent of θ and depends only on ρ and ϕ. Laplace’s equation in spherical coordinates (with
independence from θ)is
2
2
∂ u 2 ∂u 1 ∂ u cot(ϕ) ∂u
2
∇ u(ρ,ϕ) = + + + = 0.
∂ρ 2 ρ ∂ρ ρ ∂ϕ 2 ρ 2 ∂ϕ
2
The temperature on the surface is u(R,ϕ) = f (ϕ) with f being given.
Let u(ρ,ϕ) = X(ρ)
(ϕ) to obtain
2 1 cot(ϕ)
X
+ X
+ X
+ X
= 0.
ρ ρ 2 ρ 2
Upon dividing this equation by X
, we can separate the variables, obtaining
X X
+ cot(ϕ) =−ρ 2 − 2ρ =−λ.
X X
Then
2
ρ X + 2ρX − λX = 0 and
+ cot(ϕ)
+ λ
= 0.
To solve this equation for
, write it as
1
[
sin(ϕ)] + λ
= 0. (18.5)
sin(ϕ)
Change variables by putting x = cos(ϕ). Then ϕ = arccos(x).Let
G(x) =
(arccos(x)).
Since 0 ≤ ϕ ≤ π, then −1 ≤ x ≤ 1. Compute
d
dx
(ϕ)sin(ϕ) = sin(ϕ)
dx dϕ
= sin(ϕ)G (x)[−sin(ϕ)]
2
2
=−sin (ϕ)G (x) =−[1 − cos (x)]G (x)
2
=−(1 − x )G (x).
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October 14, 2010 15:27 THM/NEIL Page-656 27410_18_ch18_p641-666

